MySQL将多个表中的记录插入到新表中

I'm trying to populate a new table with records from 2 other tables.

我正在尝试用其他2个表中的记录填充新表。

period_states is new/empty

period_states是new / empty

 period_states
   id
   period_id
   sla_id

periods - contains 15 records

期间 - 包含15条记录

periods
  id

slas - contains 84 records

slas - 包含84条记录

slas
  id

I need to populate period_states with each existing sla_id having each exiting period_id. So, ultimately there should be 1260 records in period_states.

我需要使用每个现有的sla_id填充period_states,每个sla_id都有一个exiting period_id。所以,最终在period_states中应该有1260条记录。

Any idea how to automate this? It would be a nightmare to populate manually...

知道如何自动化吗?手动填充将是一场噩梦......

Thank you in advance!!

先感谢您!!

4 个解决方案

#1

INSERT INTO period_states
(period_id, sla_id)
SELECT periods.id, slas.id
FROM periods
CROSS JOIN slas

#2

If the id column of period states is defined as AUTO_INCREMENT, then this should work:

如果句点状态的id列定义为AUTO_INCREMENT,那么这应该有效:

INSERT INTO period_states (period_id, sla_id)
SELECT p.id AS period_id
     , s.id AS sla_id
  FROM periods p
 CROSS
  JOIN slas s

And here's an example of one way to supply a value for the id column:

这是一个为id列提供值的方法的示例:

INSERT INTO period_states (id, period_id, sla_id)
SELECT @myid := @myid + 1 AS id
     , p.id AS period_id
     , s.id AS sla_id
  FROM periods p
 CROSS
  JOIN slas s
 CROSS
  JOIN (SELECT @myid := 0) m

#3

insert into period_states select null, periods.id, slas.id from periods, slas

#4

Check out the "insert into.... select" http://dev.mysql.com/doc/refman/5.1/en/insert-select.html syntax. ... pretty much like what the other answers have displayed.

查看“插入....选择”http://dev.mysql.com/doc/refman/5.1/en/insert-select.html语法。 ......几乎与其他答案所显示的一样。

#1

INSERT INTO period_states
(period_id, sla_id)
SELECT periods.id, slas.id
FROM periods
CROSS JOIN slas

#2