从一个表中加入两个select语句

i have a table named attendance with 2 attributes (id, remarks). i want to display the tally of absence or late per id from the attendance table.

我有一个名为出勤的表,有2个属性(id,备注)。我想从出勤表中显示缺席或迟到的每个身份证。

Attendance Table
|ID         | Remarks       |
=============================
|1          | Absent        |
|1          | Late          |
|2          | Absent        |
|2          | Absent        |
|3          | Late          |

Sample Output
|ID         | Absent   | Late    |
==================================
|1          | 1        | 1       |
|2          | 2        |         |
|3          |          | 1       |

currently, i can only output 2 columns, (ID and Absent) or (ID and Late) using this code:

目前,我只能使用以下代码输出2列(ID和Absent)或(ID和Late):

SELECT id, count(remarks) AS Absent 
FROM attendance 
WHERE remarks = 'Absent' 
GROUP BY id;

i can't display absent and late column simultaneously.. please help. thanks.

我不能同时显示缺席和晚期列..请帮忙。谢谢。

3 个解决方案

#1

This is basically a PIVOT. If you do not have access to a PIVOT function then, you can replicate it with an aggregate function and a CASE statement:

这基本上是一个PIVOT。如果您无权访问PIVOT函数,则可以使用聚合函数和CASE语句复制它:

select id,
  sum(case when remarks = 'Absent' then 1 else 0 end) Absent,
  sum(case when remarks = 'Late' then 1 else 0 end) Late
from attendance
group by id

See SQL Fiddle with Demo

请参阅SQL Fiddle with Demo

Or you can use COUNT():

或者您可以使用COUNT():

select id,
  count(case when remarks = 'Absent' then 1 else null end) Absent,
  count(case when remarks = 'Late' then 1 else null end) Late
from attendance
group by id;

See SQL Fiddle with Demo

请参阅SQL Fiddle with Demo

#2

try:

 SELECT id, 
     Sum (Case remarks When 'Absent' Then 1 End) Absent,
     Sum (Case remarks When 'Late' Then 1 End) Late
 FROM attendance 
 GROUP BY id;

#3

Use a SUM(CASE) construct to separate the Absent and Late. For each one, the CASE returns a 1 or 0 if the value is matched, and then those are added up via the aggregate SUM() giving the total number. The concept at work here is known as a pivot table.

使用SUM(CASE)构造来分离Absent和Late。对于每一个,如果值匹配,则CASE返回1或0,然后通过汇总SUM()给出总数。这里的工作概念称为数据透视表。

SELECT
  id,
  SUM(CASE WHEN Remarks = 'Absent' THEN 1 ELSE 0 END) AS Absent,
  SUM(CASE WHEN Remarks = 'Late' THEN 1 ELSE 0 END) AS Late
FROM
  attendance
GROUP BY id