i have one String[]
我有一个String []
String[] name = {"amit", "rahul", "surya"};
i want to send name as parameter in sql query inside IN clause so how do i convert into a format
我想在IN子句中的sql查询中发送名称作为参数,那么我如何转换为格式
'amit','rahul','surya'
20 个解决方案
#1
26
if (name.length > 0) {
StringBuilder nameBuilder = new StringBuilder();
for (String n : name) {
nameBuilder.append("'").append(n.replace("'", "\\'")).append("',");
// can also do the following
// nameBuilder.append("'").append(n.replace("'", "''")).append("',");
}
nameBuilder.deleteCharAt(nameBuilder.length() - 1);
return nameBuilder.toString();
} else {
return "";
}
#2
140
Either write a simple method yourself, or use one of the various utilities out there.
要么自己编写一个简单的方法,要么使用其中的各种实用程序。
Personally I use apache StringUtils (StringUtils.join)
我个人使用apache StringUtils(StringUtils.join)
edit: in Java 8, you don't need this at all anymore:
编辑:在Java 8中,您根本不再需要它:
String joined = String.join(",", name);
#3
66
Android developers are probably looking for TextUtils.join
Android开发人员可能正在寻找TextUtils.join
Android docs: http://developer.android.com/reference/android/text/TextUtils.html
Android文档:http://developer.android.com/reference/android/text/TextUtils.html
Code:
码:
String[] name = {"amit", "rahul", "surya"};
TextUtils.join(",",name)
#4
47
StringBuilder sb = new StringBuilder();
for (String n : name) {
if (sb.length() > 0) sb.append(',');
sb.append("'").append(n).append("'");
}
return sb.toString();
#5
26
You can also use org.apache.commons.lang.StringUtils
API to form a comma separated result from string array in Java.
您还可以使用org.apache.commons.lang.StringUtils API在Java中与字符串数组形成逗号分隔的结果。
StringUtils.join(strArr,",");
StringUtils.join(strArr, “”);
#6
17
Nice and simple: but java8 required!
好又简单:但需要java8!
String result = String.join(",", names);
String result = String.join(“,”,names);
#7
9
If you already have Spring Framework as a dependency, you could also use the very simple util method:
如果您已经将Spring Framework作为依赖项,那么您还可以使用非常简单的util方法:
org.springframework.util.StringUtils.arrayToCommaDelimitedString(String[] array)
#8
6
You could also simplify it using the Guava library:
您还可以使用Guava库简化它:
String[] name = {"amit", "rahul", "surya"};
String str = "'" + Joiner.on(",").skipNulls().join(name)
.replace(",", "','") + "'";
#9
5
use StringBuilder
and iterate over your String[], and append each String into it:
使用StringBuilder并遍历String [],并将每个String追加到其中:
public static String convert(String[] name) {
StringBuilder sb = new StringBuilder();
for (String st : name) {
sb.append('\'').append(st).append('\'').append(',');
}
if (name.length != 0) sb.deleteCharAt(sb.length()-1);
return sb.toString();
}
#10
3
You can do this with one line of code:
您可以使用一行代码执行此操作:
Arrays.toString(strings).replaceAll("[\\[.\\].\\s+]", "");
#11
2
String[] name = {"amit", "rahul", "surya"};
public static String arrayToString(String array[])
{
if (array.length == 0) return "";
StringBuilder sb = new StringBuilder();
for (int i = 0; i < array.length; ++i)
{
sb.append(",'").append(array[i]).append("'");
}
return sb.substring(1);
}
#12
2
i use this
我用这个
public static String convertToCommaSeparated(String[] strings) {
StringBuffer sb = new StringBuffer("");
for (int i = 0; strings != null && i < strings.length; i++) {
sb.append(strings[i]);
if (i < strings.length - 1) {
sb.append(',');
}
}
return sb.toString();
}
#13
1
String[] paramIdIdList={"P001","P002","P003"};
StringBuilder builder = new StringBuilder();
for(String paramId : paramIdIdList) {
builder.append(paramId+",");
}
builder.deleteCharAt(builder.length() -1);
String paramIds = builder.toString();
System.Out.Println(paramIds );
#14
1
As tempting and "cool" as the code may appear, do not use fold
or reduce
on large collections of strings, as these will suffer from the string concatenation problem
由于代码可能出现诱惑和“酷”,不要在大型字符串集合上使用fold或reduce,因为这些将受到字符串连接问题的影响
String[] strings = { "foo", "bar", "baz" };
Optional<String> result = Arrays.stream(strings)
.reduce((a, b) -> String.format("%s,%s", a, b));
System.out.println(result.get());
Instead, as per other answers, use String.join()
if you already have a collection, or a StringBuilder
if not.
相反,根据其他答案,如果您已经有一个集合,则使用String.join(),否则使用StringBuilder。
#15
0
String newNameList=null;
for(int i = name.length;i>=0;i--){
if(newNameList==null){
newNameList = "\'" + name[name.length - i] + "\'";
}
else{
newNameList += ",\'" + name[name.length - i] + "\'";
}
}
#16
0
You may also want not to spawn StringBuilder for such simple operation. Please note that I've changed name of your array from name to names for sake of content conformity:
您可能还希望不为这种简单的操作生成StringBuilder。请注意,为了符合内容,我已将名称的名称从名称更改为名称:
String[] names = {"amit", "rahul", "surya"};
String namesString = "";
int delimeters = (names.size() - 1);
for (String name : names)
namesString += (delimeters-- > 0) ? "'" + name + "'," : "'" + name + "'";
#17
0
Two lines (excluding declarations; 'finalstring' should be initially declared equal to an empty string), if you don't care a lot about vertically spacing the for() loop:
两行(不包括声明;'finalstring'应该最初声明等于空字符串),如果你不太关心垂直间隔for()循环:
for (int i = 0; i<string_array.length; i++) {finalstring += string_array[i]+",";}
finalstring = finalstring.substring(0,finalstring.length()-1);
Two lines, you're done. :)
两行,你完成了。 :)
#18
0
here is a Utility method to split an array and put your custom delimiter, using
这是一个实用的方法来分割数组并使用自定义分隔符
String.replace(String,String)
Arrays.toString(Object[])
here it is :
这里是 :
public static String toString(String delimiter, Object[]array){
String s = "";
// split array
if (array != null && array.length > 0) {
s = Arrays.toString(array).replace("[", "").replace("]", "");
}
// place delimiter (notice the space in ", ")
if(delimiter != null){
s = s.replace(", ", delimiter);
}
return s;
}
change the second argument type to suite your array type
更改第二个参数类型以适应您的数组类型
#19
0
This would be an optimized way of doing it
这将是一种优化的方式
StringBuilder sb = new StringBuilder();
for (String n : arr) {
sb.append("'").append(n).append("',");
}
if(sb.length()>0)
sb.setLength(sbDiscrep.length()-1);
return sb.toString();
#20
-1
USE StringUtils.join
function: E.g.
USE StringUtils.join函数:例如
String myCsvString = StringUtils.join(myList, ",")
#1
26
if (name.length > 0) {
StringBuilder nameBuilder = new StringBuilder();
for (String n : name) {
nameBuilder.append("'").append(n.replace("'", "\\'")).append("',");
// can also do the following
// nameBuilder.append("'").append(n.replace("'", "''")).append("',");
}
nameBuilder.deleteCharAt(nameBuilder.length() - 1);
return nameBuilder.toString();
} else {
return "";
}
#2
140
Either write a simple method yourself, or use one of the various utilities out there.
要么自己编写一个简单的方法,要么使用其中的各种实用程序。
Personally I use apache StringUtils (StringUtils.join)
我个人使用apache StringUtils(StringUtils.join)
edit: in Java 8, you don't need this at all anymore:
编辑:在Java 8中,您根本不再需要它:
String joined = String.join(",", name);
#3
66
Android developers are probably looking for TextUtils.join
Android开发人员可能正在寻找TextUtils.join
Android docs: http://developer.android.com/reference/android/text/TextUtils.html
Android文档:http://developer.android.com/reference/android/text/TextUtils.html
Code:
码:
String[] name = {"amit", "rahul", "surya"};
TextUtils.join(",",name)
#4
47
StringBuilder sb = new StringBuilder();
for (String n : name) {
if (sb.length() > 0) sb.append(',');
sb.append("'").append(n).append("'");
}
return sb.toString();
#5
26
You can also use org.apache.commons.lang.StringUtils
API to form a comma separated result from string array in Java.
您还可以使用org.apache.commons.lang.StringUtils API在Java中与字符串数组形成逗号分隔的结果。
StringUtils.join(strArr,",");
StringUtils.join(strArr, “”);
#6
17
Nice and simple: but java8 required!
好又简单:但需要java8!
String result = String.join(",", names);
String result = String.join(“,”,names);
#7
9
If you already have Spring Framework as a dependency, you could also use the very simple util method:
如果您已经将Spring Framework作为依赖项,那么您还可以使用非常简单的util方法:
org.springframework.util.StringUtils.arrayToCommaDelimitedString(String[] array)
#8
6
You could also simplify it using the Guava library:
您还可以使用Guava库简化它:
String[] name = {"amit", "rahul", "surya"};
String str = "'" + Joiner.on(",").skipNulls().join(name)
.replace(",", "','") + "'";
#9
5
use StringBuilder
and iterate over your String[], and append each String into it:
使用StringBuilder并遍历String [],并将每个String追加到其中:
public static String convert(String[] name) {
StringBuilder sb = new StringBuilder();
for (String st : name) {
sb.append('\'').append(st).append('\'').append(',');
}
if (name.length != 0) sb.deleteCharAt(sb.length()-1);
return sb.toString();
}
#10
3
You can do this with one line of code:
您可以使用一行代码执行此操作:
Arrays.toString(strings).replaceAll("[\\[.\\].\\s+]", "");
#11
2
String[] name = {"amit", "rahul", "surya"};
public static String arrayToString(String array[])
{
if (array.length == 0) return "";
StringBuilder sb = new StringBuilder();
for (int i = 0; i < array.length; ++i)
{
sb.append(",'").append(array[i]).append("'");
}
return sb.substring(1);
}
#12
2
i use this
我用这个
public static String convertToCommaSeparated(String[] strings) {
StringBuffer sb = new StringBuffer("");
for (int i = 0; strings != null && i < strings.length; i++) {
sb.append(strings[i]);
if (i < strings.length - 1) {
sb.append(',');
}
}
return sb.toString();
}
#13
1
String[] paramIdIdList={"P001","P002","P003"};
StringBuilder builder = new StringBuilder();
for(String paramId : paramIdIdList) {
builder.append(paramId+",");
}
builder.deleteCharAt(builder.length() -1);
String paramIds = builder.toString();
System.Out.Println(paramIds );
#14
1
As tempting and "cool" as the code may appear, do not use fold
or reduce
on large collections of strings, as these will suffer from the string concatenation problem
由于代码可能出现诱惑和“酷”,不要在大型字符串集合上使用fold或reduce,因为这些将受到字符串连接问题的影响
String[] strings = { "foo", "bar", "baz" };
Optional<String> result = Arrays.stream(strings)
.reduce((a, b) -> String.format("%s,%s", a, b));
System.out.println(result.get());
Instead, as per other answers, use String.join()
if you already have a collection, or a StringBuilder
if not.
相反,根据其他答案,如果您已经有一个集合,则使用String.join(),否则使用StringBuilder。
#15
0
String newNameList=null;
for(int i = name.length;i>=0;i--){
if(newNameList==null){
newNameList = "\'" + name[name.length - i] + "\'";
}
else{
newNameList += ",\'" + name[name.length - i] + "\'";
}
}
#16
0
You may also want not to spawn StringBuilder for such simple operation. Please note that I've changed name of your array from name to names for sake of content conformity:
您可能还希望不为这种简单的操作生成StringBuilder。请注意,为了符合内容,我已将名称的名称从名称更改为名称:
String[] names = {"amit", "rahul", "surya"};
String namesString = "";
int delimeters = (names.size() - 1);
for (String name : names)
namesString += (delimeters-- > 0) ? "'" + name + "'," : "'" + name + "'";
#17
0
Two lines (excluding declarations; 'finalstring' should be initially declared equal to an empty string), if you don't care a lot about vertically spacing the for() loop:
两行(不包括声明;'finalstring'应该最初声明等于空字符串),如果你不太关心垂直间隔for()循环:
for (int i = 0; i<string_array.length; i++) {finalstring += string_array[i]+",";}
finalstring = finalstring.substring(0,finalstring.length()-1);
Two lines, you're done. :)
两行,你完成了。 :)
#18
0
here is a Utility method to split an array and put your custom delimiter, using
这是一个实用的方法来分割数组并使用自定义分隔符
String.replace(String,String)
Arrays.toString(Object[])
here it is :
这里是 :
public static String toString(String delimiter, Object[]array){
String s = "";
// split array
if (array != null && array.length > 0) {
s = Arrays.toString(array).replace("[", "").replace("]", "");
}
// place delimiter (notice the space in ", ")
if(delimiter != null){
s = s.replace(", ", delimiter);
}
return s;
}
change the second argument type to suite your array type
更改第二个参数类型以适应您的数组类型
#19
0
This would be an optimized way of doing it
这将是一种优化的方式
StringBuilder sb = new StringBuilder();
for (String n : arr) {
sb.append("'").append(n).append("',");
}
if(sb.length()>0)
sb.setLength(sbDiscrep.length()-1);
return sb.toString();
#20
-1
USE StringUtils.join
function: E.g.
USE StringUtils.join函数:例如
String myCsvString = StringUtils.join(myList, ",")