如何将逗号分隔的字符串转换为LIST或IEnumerable的KeyValuePair

I have a dynamic string:

我有一个动态字符串：

It looks like "1: Name, 2: Another Name" this. I want to split it and convert it to a List<KeyValuePair<int, string>> or IEnmerable<KeyValuePair<int, string>>

它看起来像“1：名字，2：另一个名字”。我想拆分它并将其转换为List >或IEnmerable >

I tried this.

我试过这个。

myString.Split(',').Select(s => s => new KeyValuePair<int, string>( Convert.ToInt32(s.Substring(s.LastIndexOf(':'), s.Substring(0, s.LastIndexOf(':')) + 1))))

Does not to help much. I can do strings of Dictionary or a foreach or a for loop. I rather do it as a key value pair lambda expression one liner.

没有多大帮助。我可以做Dictionary或foreach或for循环的字符串。我宁愿做一个关键值对lambda表达式一个衬垫。

4 个解决方案

#1

Try this:

尝试这个：

myString.Split(',').Select(s => new KeyValuePair<int, string>(
   int.Parse(s.Split(':').GetValue(0).ToString()),
   s.Split(':').GetValue(1).ToString()
));

#2

You need to split twice first by comma, then by colon. Try this code:

您需要先用逗号分割两次，然后用冒号分割。试试这段代码：

var input = "1: Name, 2: Another Name";

var list = input.Split(',')
    .Select(p =>
    {
        var kv = p.Split(':');
        return new KeyValuePair<int, string>(int.Parse(kv[0].Trim()), kv[1]);
    })
    .ToList();

#3

One-liner:

一内胆：

WARNING: No exception handling

警告：无异常处理

myString.Split(',').Select(x => new KeyValuePair<int, string>(int.Parse(x.Split(':')[0]), x.Split(':')[1]))

#4

Another way to achieve that with the beauty of regex:

用正则表达式之美来实现这一目标的另一种方法：

var result = new List<KeyValuePair<int, string>>();
foreach (Match match in Regex.Matches("1: Name, 2: Another Name", @"((\d+): ([\w ]+))"))
{
    result.Add(new KeyValuePair<int, string>(int.Parse(match.Groups[2].Value), match.Groups[3].Value));
}

#1