使用递归自联接的Mysql查询

时间:2022-04-16 00:13:39

I am trying to write a query with a recursive self join. My tables are something as below:

我正在尝试使用递归自联接编写查询。我的表格如下:

Table1

EMP_ID      Name
1          Manger1 
2          Manger2
3          Manger3
4          Employ1
5          Employ2

Table2

Par_EMP_ID   EMP_ID   
1                2
2                3
3                4
3                5  

Here in above tables the Manager1, Manager2, ..., Employe2 are employees in a company where Manager1 is Head of Dept. Manager2 is reporting to Manager1, Manager3 is reporting to Manager2, this relation ship is maintained in table2 where Par_EMP_ID is EMP_ID of reportii and column EMP_ID is id of reporter. Now I want result as below:

在上面的表中,Manager1,Manager2,...,Employe2是Manager1是部门主管的公司中的员工.Manager2向Manager1报告,Manager3向Manager2报告,此关系在表2中维护,其中Par_EMP_ID是EMP_ID reportii和列EMP_ID是记者的id。现在我想要结果如下:

Manager1      Manager2   Manager3  Employe1
Manager1      Manager2   Manager3  Employe2

1 个解决方案

#1


1  

UPDATE:

According to your specs, here's the solution:

根据您的规格,这是解决方案:

SELECT  e.names member, d.name child
    FROM MEMBERS d INNER JOIN
        (SELECT a.id, GROUP_CONCAT(c.name) NAMES
            FROM MEMBERS a
    INNER JOIN RELATIONSHIP b ON a.id = b.MEM_ID
INNER JOIN MEMBERS c ON c.id = b.PAR_MEM_ID
GROUP BY a.id) e ON e.id = d.id

Result:

|             MEMBER |        CHILD |
|--------------------|--------------|
| Great Grand Father | Grand Father |
|       Grand Father |       Father |
|             Father |       Child1 |
|             Father |       Child2 |

Note:the results may depend on your sample data. And I updated also the SQLFiddle below so you might want to check that out.

注意:结果可能取决于您的样本数据。我还更新了下面的SQLFiddle,所以你可能想要检查出来。

Here's the SQLFiddle.

这是SQLFiddle。

#1


1  

UPDATE:

According to your specs, here's the solution:

根据您的规格,这是解决方案:

SELECT  e.names member, d.name child
    FROM MEMBERS d INNER JOIN
        (SELECT a.id, GROUP_CONCAT(c.name) NAMES
            FROM MEMBERS a
    INNER JOIN RELATIONSHIP b ON a.id = b.MEM_ID
INNER JOIN MEMBERS c ON c.id = b.PAR_MEM_ID
GROUP BY a.id) e ON e.id = d.id

Result:

|             MEMBER |        CHILD |
|--------------------|--------------|
| Great Grand Father | Grand Father |
|       Grand Father |       Father |
|             Father |       Child1 |
|             Father |       Child2 |

Note:the results may depend on your sample data. And I updated also the SQLFiddle below so you might want to check that out.

注意:结果可能取决于您的样本数据。我还更新了下面的SQLFiddle,所以你可能想要检查出来。

Here's the SQLFiddle.

这是SQLFiddle。