I'm beginner in SQl,how can i do this in that ? is this possible ?
我是SQl的初学者,我怎么能这样做呢?这可能吗 ?
1 个解决方案
#1
3
You can use the PIVOT
table operator to do transform the rows of these course's grades into column, like so:
您可以使用PIVOT表运算符将这些课程成绩的行转换为列,如下所示:
SELECT
Course,
[1] AS "Grade 1",
[2] AS "Grade 2",
[3] AS "Grade 3",
[4] AS "Grade 4"
FROM
(
SELECT
Course,
Grade,
ROW_NUMBER() OVER(PARTITION BY Course
ORDER BY COURSE) rownum
FROM Grades
) t
PIVOT
(
MAX(Grade)
FOR rownum IN([1], [2], [3], [4])
) p;
SQL Fiddle Demo
This will give you:
这会给你:
COURSE GRADE 1 GRADE 2 GRADE 3 GRADE 4
A 15 17 (null) (null)
B 12 (null) (null) (null)
C 10 18 0 9
Note that: I used the ranking function ROW_NUMBER()
with PARTITION BY Course
to partition them into four grades. So that you could then group them into these four groups.
请注意:我使用PARTITION BY课程的排名函数ROW_NUMBER()将它们分成四个等级。这样你就可以将它们分成这四组。
If you need to this dynamically, in case there was unknown number of grades. You can use dynamic SQL in this case to generate the list of grades dynamically like so:
如果你需要动态,如果有不明数量的成绩。在这种情况下,您可以使用动态SQL动态生成成绩列表,如下所示:
DECLARE @cols AS NVARCHAR(MAX);
DECLARE @query AS NVARCHAR(MAX);
SELECT @cols = STUFF((SELECT distinct ','
+ QUOTENAME('Grade '
+ CAST(ROW_NUMBER() OVER(PARTITION BY Course
ORDER BY Course) AS VARCHAR(10)))
FROM Grades
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)'), 1, 1, '');
SELECT @query = 'SELECT Course, ' + @cols +
'FROM
(
SELECT
Course,
Grade,
''Grade '' + CAST(ROW_NUMBER()
OVER(PARTITION BY Course
ORDER BY COURSE) AS VARCHAR(10)) rownum
FROM Grades
) t
PIVOT
(
MAX(Grade)
FOR rownum IN(' + @cols + ')' +
') p';
execute(@query);
Dynamic SQL Fiddle Demo
#1
3
You can use the PIVOT
table operator to do transform the rows of these course's grades into column, like so:
您可以使用PIVOT表运算符将这些课程成绩的行转换为列,如下所示:
SELECT
Course,
[1] AS "Grade 1",
[2] AS "Grade 2",
[3] AS "Grade 3",
[4] AS "Grade 4"
FROM
(
SELECT
Course,
Grade,
ROW_NUMBER() OVER(PARTITION BY Course
ORDER BY COURSE) rownum
FROM Grades
) t
PIVOT
(
MAX(Grade)
FOR rownum IN([1], [2], [3], [4])
) p;
SQL Fiddle Demo
This will give you:
这会给你:
COURSE GRADE 1 GRADE 2 GRADE 3 GRADE 4
A 15 17 (null) (null)
B 12 (null) (null) (null)
C 10 18 0 9
Note that: I used the ranking function ROW_NUMBER()
with PARTITION BY Course
to partition them into four grades. So that you could then group them into these four groups.
请注意:我使用PARTITION BY课程的排名函数ROW_NUMBER()将它们分成四个等级。这样你就可以将它们分成这四组。
If you need to this dynamically, in case there was unknown number of grades. You can use dynamic SQL in this case to generate the list of grades dynamically like so:
如果你需要动态,如果有不明数量的成绩。在这种情况下,您可以使用动态SQL动态生成成绩列表,如下所示:
DECLARE @cols AS NVARCHAR(MAX);
DECLARE @query AS NVARCHAR(MAX);
SELECT @cols = STUFF((SELECT distinct ','
+ QUOTENAME('Grade '
+ CAST(ROW_NUMBER() OVER(PARTITION BY Course
ORDER BY Course) AS VARCHAR(10)))
FROM Grades
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)'), 1, 1, '');
SELECT @query = 'SELECT Course, ' + @cols +
'FROM
(
SELECT
Course,
Grade,
''Grade '' + CAST(ROW_NUMBER()
OVER(PARTITION BY Course
ORDER BY COURSE) AS VARCHAR(10)) rownum
FROM Grades
) t
PIVOT
(
MAX(Grade)
FOR rownum IN(' + @cols + ')' +
') p';
execute(@query);