I'm trying to make a condition that matches any amount of spaces in a file name $f. But what I have seems to be matching everything?
我正在尝试创建一个条件来匹配文件名$f中任意数量的空格。但我所拥有的似乎是匹配一切的呢?
if [[ $f =~ [[:space:]]* ]]; then
echo found a space
fi
This matches i-have-no-spaces.jpg as well as i have spaces.jpg
这和我没有空间。jpg和我有空间。jpg一样
1 个解决方案
#1
2
Don't use *, it means 0 or more matches.
不要使用*，它意味着0或更多的匹配。
Use
使用
if [[ $f =~ [[:space:]] ]]; then
echo "found a space"
fi
However in BASH, I suggest to not to use regex for this, just use glob matching with =:
但是在BASH中，我建议不要对此使用regex，只使用与=匹配的glob:
if [[ $f = *[[:space:]]* ]]; then
echo "found a space"
fi
#1
2
Don't use *, it means 0 or more matches.
不要使用*，它意味着0或更多的匹配。
Use
使用
if [[ $f =~ [[:space:]] ]]; then
echo "found a space"
fi
However in BASH, I suggest to not to use regex for this, just use glob matching with =:
但是在BASH中，我建议不要对此使用regex，只使用与=匹配的glob:
if [[ $f = *[[:space:]]* ]]; then
echo "found a space"
fi