在使用SQL进行分组时，计算行之间的差异

I have a postgresql table containing movements of different items (models) between warehouses.

我有一个postgresql表，其中包含仓库之间不同项目(模型)的移动。

For example, the following record means that 5 units of model 1 have been sent form warehouse 1 to 2:

例如，下面的记录表示模型1的5个单元已经从仓库1发送到仓库2:

source target model units
------ ------ ----- -----
     1      2     1     5

I am trying to build a SQL query to obtain the difference between units sent and received, grouped by models. Again with an example:

我正在尝试构建一个SQL查询，以获得发送和接收单元之间的差异，并按模型分组。又用一个例子:

source target model units
------ ------ ----- -----
     1      2     1     5  -- 5 sent from 1 to 2
     1      2     2     1
     2      1     1     2  -- 2 sent from 2 to 1
     2      1     1     1  -- 1 more sent from 2 to 1

The result should be:

结果应该是:

source target model diff
------ ------ ----- ----
     1      2     1    2   -- 5 sent minus 3 received
     1      2     2    1

I wonder if this is possible with a single SQL query.

我想知道是否可以使用一个SQL查询。

Here is the table creation script and some data, just in case anyone wants to try it:

这里是表创建脚本和一些数据，以防有人想尝试:

CREATE TEMP TABLE movements
(
    source  INTEGER,
    target  INTEGER,
    model   INTEGER,
    units   INTEGER
);

insert into movements values (1,2,1,5);
insert into movements values (1,2,2,1);
insert into movements values (2,1,1,2);
insert into movements values (2,1,1,1);

2 个解决方案

#1

Does this do what you need? I don't have an Oracle DB to test against so I hope the rules on Grouping expressions are the same as for MS SQL Server

这能满足你的需要吗?我没有一个Oracle DB来测试，所以我希望对分组表达式的规则与MS SQL Server相同。

SELECT     
 CASE WHEN source < target THEN source ELSE target END AS source,
 CASE WHEN source < target THEN target ELSE source END AS target,
 SUM(CASE WHEN source < target THEN units ELSE -units END) AS Diff, 
    model
FROM  movements
GROUP BY
 CASE WHEN source < target THEN source ELSE target END,
 CASE WHEN source < target THEN target ELSE source END,
    model

#2

You can do this with two subselects which sum the movements in each direction, and then union and sum the results of those two subqueries:

你可以用两个子选择来完成这两个子选择，分别对每个方向的运动求和，然后结合两个子查询的结果:

SELECT source, target, model, SUM(units)
FROM (
    SELECT source, target, model, SUM(units) AS units
    FROM movements
    WHERE source < target
    GROUP BY source, target, model
    UNION ALL
    SELECT target, source, model, SUM(-units) AS units
    FROM movements
    WHERE source > target
    GROUP BY source, target, model
) T1
GROUP BY source, target, model

#1