I have the following query that selects * where display in the Zips table is equal to a column in the users table.
我有以下查询选择*,在Zips表中显示的位置等于users表中的列。
This works fine, but how do I select ANOTHER column from the Zips table to print it out?
这很好,但是如何从Zips表中选择另一列来打印它呢?
Zip.where(:display => @user.location)
邮政编码。(:显示= > @user.location)
So, for example the users table has a location
col and the zips table has a display
and zipcode
column. I am finding the proper row by matching location
from users to the display
in zips but need to pull out zipcodes from the matching entry in zips...
例如,users表有一个location col, zips表有一个display和zipcode列。我通过将用户的位置匹配到以zips显示的位置来找到正确的行,但是需要从以zips匹配的条目中提取zipcode…
1 个解决方案
#1
1
Assuming your Zip
table has the zipcode
field:
假设您的Zip表有zipcode字段:
@zips = Zip.where(:display => @user.location)
@zips.each do |zip|
puts zip.zipcode
end
Or to put them in an array:
或者把它们放在数组中:
zipcodes = @zips.collect{ |zip| zip.zipcode }
In a view:
在一个视图:
<h3>Zip Codes</h3>
<ul>
<% @zips.each do |zip| %>
<li><%= zip.zipcode %></li>
<% end %>
</ul>
#1
1
Assuming your Zip
table has the zipcode
field:
假设您的Zip表有zipcode字段:
@zips = Zip.where(:display => @user.location)
@zips.each do |zip|
puts zip.zipcode
end
Or to put them in an array:
或者把它们放在数组中:
zipcodes = @zips.collect{ |zip| zip.zipcode }
In a view:
在一个视图:
<h3>Zip Codes</h3>
<ul>
<% @zips.each do |zip| %>
<li><%= zip.zipcode %></li>
<% end %>
</ul>