Sample Input
1
5 6
orz
sto
kirigiri
danganronpa
ooooo
o
kyouko
dangan
ronpa
ooooo
ooooo
5 6
orz
sto
kirigiri
danganronpa
ooooo
o
kyouko
dangan
ronpa
ooooo
ooooo
Sample Output
1
1
0
3
7
1
0
3
7
题意:给n个母串,给m个匹配串,求每个母串依次和匹配串匹配,能得到的数目和
开始用KMP超时了,突然看见AC,把模板改一下就过了- -
#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
using namespace std;
#define N 500010
char str[10010], keyword[10005];
char l[100005][10005];
int head, tail; struct node
{
node *fail;
node *next[26];
int count;
node() //init
{
fail = NULL;
count = 0;
for(int i = 0; i < 26; ++i)
next[i] = NULL;
}
}*q[N];
node *root; void insert(char *str) //建立Trie
{
int temp, len;
node *p = root;
len = strlen(str);
for(int i = 0; i < len; ++i)
{
temp = str[i] - 'a';
if(p->next[temp] == NULL)
p->next[temp] = new node();
p = p->next[temp];
}
p->count++;
} void build_ac()
{
q[tail++] = root;
while(head != tail)
{
node *p = q[head++];
node *temp = NULL;
for(int i = 0; i < 26; ++i)
{
if(p->next[i] != NULL)
{
if(p == root)
p->next[i]->fail = root;
else
{
temp = p->fail;
while(temp != NULL)
{
if(temp->next[i] != NULL)
{
p->next[i]->fail = temp->next[i];
break;
}
temp = temp->fail;
}
if(temp == NULL)
p->next[i]->fail = root;
}
q[tail++] = p->next[i]; //入队
}
}
}
} int query()
{
int index, len, result;
node *p = root; //Tire入口
result = 0;
len = strlen(str);
for(int i = 0; i < len; ++i)
{
index = str[i] - 'a';
while(p->next[index] == NULL && p != root)
p = p->fail;
p = p->next[index];
if(p == NULL)
p = root;
node *temp = p;
while(temp != root && temp->count != -1)
{
result += temp->count;
//temp->count = -1;
temp = temp->fail;
}
}
return result;
} int main()
{
int ncase, num,n;
scanf("%d", &ncase);
while(ncase--)
{
head= tail = 0;
root = new node();
scanf("%d%d", &n,&num);
getchar();
for(int i = 1;i <= n;i++)
gets(l[i]);
for(int i = 0; i < num; ++i)
{
gets(keyword);
insert(keyword);
}
build_ac();
for(int i = 1; i <= n; i++)
{
memccpy(str,l[i],0,sizeof(l[i]));
//build_ac();
printf("%d\n", query());
}
}
return 0;
}