使用SqlAlchemy选择和连接函数创建SQL查询

时间:2021-07-19 22:52:02

I have two tables "tags" and "deal_tag", and table definition follows,

我有两个表“tags”和“deal_tag”,表格定义如下,

Table('tags', metadata,
          Column('id', types.Integer(), Sequence('tag_uid_seq'),
              primary_key=True),
          Column('name', types.String()),
         )

Table('deal_tag', metadata,
       Column('dealid', types.Integer(), ForeignKey('deals.id')),
       Column('tagid', types.Integer(), ForeignKey
           ('tags.id')),
        )

I want to select tag id, tag name and deal count (number of deals per tag). Sample query is

我想选择标签ID,标签名称和交易计数(每个标签的交易数量)。示例查询是

SELECT tags.Name,tags.id,COUNT(deal_tag.dealid) FROM tags INNER JOIN
deal_tag ON tags.id = deal_tag.tagid GROUP BY deal_tag.tagid;

How do I create the above query using SqlAlchemy select & join functions?

如何使用SqlAlchemy select&join函数创建上述查询?

2 个解决方案

#1


Give this a try...

尝试一下......

s = select([tags.c.Name, tags.c.id, func.count(deal_tag.dealid)], 
           tags.c.id == deal_tag.c.tagid).group_by(tags.c.Name, tags.c.id)

#2


you can join table in the time of mapping table

你可以在映射表的时候连接表

in the orm.mapper()

在orm.mapper()中

for more information you can go thru the link

有关更多信息,您可以通过链接

www.sqlalchemy.org/docs/

#1


Give this a try...

尝试一下......

s = select([tags.c.Name, tags.c.id, func.count(deal_tag.dealid)], 
           tags.c.id == deal_tag.c.tagid).group_by(tags.c.Name, tags.c.id)

#2


you can join table in the time of mapping table

你可以在映射表的时候连接表

in the orm.mapper()

在orm.mapper()中

for more information you can go thru the link

有关更多信息,您可以通过链接

www.sqlalchemy.org/docs/