题目
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" alt="" />
解决代码及点评
/*
有两个磁盘文件,各自存放已排好序的若干个字符(如a1. dat 中放"abort", a2.dat中放 "boy")
要求将两个文件合并,合并后仍保持有序,存放在a3.dat文件中。
提示:可先将两个文件中的字符存入一个字符型数组中,而后对数组重新排序,再将该数组写入a3.dat文件中。
如果不引入一个中间数组进行重新排序,该如何编程? */ #include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h> #define SWAP(x,y) {char tmp; tmp = (x); (x)=(y); (y)=tmp;} static void str_sort(char *str, int str_size)
{
int i,j; for (i = 0; i < str_size; i++)
{
for (j = str_size - 2; j >= i; j--)
{
if (str[j] > str[j+1])
{
SWAP(str[j],str[j+1]);
}
}
}
} int main()
{
FILE *fp = NULL;
char str[128] = "";
char *p = str; fopen_s(&fp, "a1.dat", "r");//打开a1.dat
if (fp == NULL)
{
fopen_s(&fp, "a1.dat", "w+");//读写
fprintf(fp, "%s", "abort");
rewind(fp);
}
fscanf_s(fp, "%s", str);
fclose(fp); p = str+strlen(str);//p移动到末尾 fopen_s(&fp, "a2.dat", "r");//打开a2.dat
if (fp == NULL)
{
fopen_s(&fp, "a2.dat", "w+");//读写
fprintf(fp, "%s", "boy");
rewind(fp);
}
fscanf_s(fp, "%s", p);
fclose(fp); str_sort(str, strlen(str));//对str[]进行排序
printf("%s\n", str); fopen_s(&fp, "a3.dat", "w");//将str写入a3.dat
fprintf(fp, "%s", str);
fclose(fp); return 0;
}
代码编译以及运行
由于资源上传太多,资源频道经常被锁定无法上传资源,同学们可以打开VS2013自己创建工程,步骤如下:
1)新建工程
2)选择工程
3)创建完工程如下图:
4)增加文件,右键点击项目
5)在弹出菜单里做以下选择
6)添加文件
7)拷贝代码与运行
程序运行结果
代码下载
http://download.csdn.net/detail/yincheng01/6694119
解压密码:c.itcast.cn