it's my first time to come here. In generally i find myself some answers but now i got a big problem with PIVOT sql server 2012. I'm just an intern and i don't know how to do PIVOTS with Multiple Tables and Columns in using PHP. So i Have 3 Tables (Equipements, Champ-perso, Equipement_Complément), I succeeded to display all the data through a SQL query using PHP. But in this display, There are equipements which are duplicate, and Champ-Perso and Equipement_Complément appear in rows. And I want to do a function PIVOT which deletes equipements duplicate, and displays Champ-Perso and Equipement_Complément in columns.
这是我第一次来这里。一般来说,我发现自己有一些答案,但现在我遇到了PIVOT sql server 2012的一个大问题。我只是一个实习生而且我不知道如何使用PHP在多个表和列中做PIVOTS。所以我有3个表(Equipements,Champ-perso,Equipement_Complément),我成功地通过使用PHP的SQL查询显示所有数据。但是在这个显示中,有一些重复的设备,并且Champ-Perso和Equipement_Complément出现在行中。我想做一个功能PIVOT删除设备重复,并在列中显示Champ-Perso和Equipement_Complément。
Here is my display
这是我的展示
`Name_Equipement Champ-Perso Equipemennt-Complément
ENG-0001 Année rénovation A
ENG-0001 Largeur utile (mm) B
ENG-0001 Nb de pinces de dépose C
ENG-0001 Nb de postes dengagement D
ENG-0001 Nb de voies E
ENG-0001 Numéro du train F
ENG-0001 Type/modèle G
ENG-0002 Année rénovation A1
ENG-0002 Largeur utile (mm) B1
ENG-0002 Nb de pinces de dépose C1
ENG-0002 Nb de postes dengagement D1
ENG-0002 Nb de voies E1
ENG-0002 Numéro du train F1
ENG-0002 Type/modèle G1
`
And i want to display
我想要展示
`Name_Equipment Année rénovation Largeur Utile (mm) ... Type:Modèle
ENG-0001 A B ... G
ENG-0002 A1 B1 ... G1
`
1 个解决方案
#1
0
Here the solution for your problem. I assume that the data shown in your question is in table #temp
.
这里是您的问题的解决方案。我假设你问题中显示的数据在表#temp中。
First you need to find unique Champ-Perso
from your table. Use below query.
首先,你需要从你的桌子上找到独特的Champ-Perso。使用以下查询。
select * into #temp1 from (select distinct([Champ-Perso]) from #temp) as A
Now write your pivot query as below...
现在编写您的透视查询,如下所示......
Declare @str nvarchar(1000)
Declare @SQL nvarchar(1000)
SELECT @str = COALESCE(@str+'],[', '') + [Champ-Perso] FROM #temp1
set @str = '[' +@str + ']'
set @SQL = N' select [Name_Equipement], ' + @str +' from (select [Name_Equipement], [Champ-Perso], [Equipemennt-Complément] from #temp) as tbl
Pivot
(
max([Equipemennt-Complément])
for [Champ-Perso] in ('+ @str+')
) as p'
To get the result, fire this query...
要获得结果,请触发此查询...
EXECUTE sp_executesql @sql
Note: Since Champ-Perso
is not common across your Name_Equipement
, so you will see NULL
whereever the value would be missing.
注意:由于Champ-Perso在您的Name_Equipement中并不常见,因此您将看到NULL,因为该值将丢失。
#1
0
Here the solution for your problem. I assume that the data shown in your question is in table #temp
.
这里是您的问题的解决方案。我假设你问题中显示的数据在表#temp中。
First you need to find unique Champ-Perso
from your table. Use below query.
首先,你需要从你的桌子上找到独特的Champ-Perso。使用以下查询。
select * into #temp1 from (select distinct([Champ-Perso]) from #temp) as A
Now write your pivot query as below...
现在编写您的透视查询,如下所示......
Declare @str nvarchar(1000)
Declare @SQL nvarchar(1000)
SELECT @str = COALESCE(@str+'],[', '') + [Champ-Perso] FROM #temp1
set @str = '[' +@str + ']'
set @SQL = N' select [Name_Equipement], ' + @str +' from (select [Name_Equipement], [Champ-Perso], [Equipemennt-Complément] from #temp) as tbl
Pivot
(
max([Equipemennt-Complément])
for [Champ-Perso] in ('+ @str+')
) as p'
To get the result, fire this query...
要获得结果,请触发此查询...
EXECUTE sp_executesql @sql
Note: Since Champ-Perso
is not common across your Name_Equipement
, so you will see NULL
whereever the value would be missing.
注意:由于Champ-Perso在您的Name_Equipement中并不常见,因此您将看到NULL,因为该值将丢失。