如何使用dplyr :: mutate_all来舍入所选列

I'm using the following package version

我正在使用以下包版本

# devtools::install_github("hadley/dplyr")
> packageVersion("dplyr")
[1] ‘0.5.0.9001’

With the following tibble:

通过以下方式:

library(dplyr)
df  <- structure(list(gene_symbol = structure(1:6, .Label = c("0610005C13Rik", 
"0610007P14Rik", "0610009B22Rik", "0610009L18Rik", "0610009O20Rik", 
"0610010B08Rik"), class = "factor"), fold_change = c(1.54037, 
1.10976, 0.785, 0.79852, 0.91615, 0.87931), pvalue = c(0.5312, 
0.00033, 0, 0.00011, 0.00387, 0.01455), ctr.mean_exp = c(0.00583, 
59.67286, 83.2847, 6.88321, 14.67696, 1.10363), tre.mean_exp = c(0.00899, 
66.22232, 65.37819, 5.49638, 13.4463, 0.97043), ctr.cv = c(5.49291, 
0.20263, 0.17445, 0.46288, 0.2543, 0.39564), tre.cv = c(6.06505, 
0.28827, 0.33958, 0.53295, 0.26679, 0.52364)), .Names = c("gene_symbol", 
"fold_change", "pvalue", "ctr.mean_exp", "tre.mean_exp", "ctr.cv", 
"tre.cv"), row.names = c(NA, -6L), class = c("tbl_df", "tbl", 
"data.frame"))

That looks like this:

看起来像这样:

> df
# A tibble: 6 × 7
    gene_symbol fold_change  pvalue ctr.mean_exp tre.mean_exp  ctr.cv  tre.cv
         <fctr>       <dbl>   <dbl>        <dbl>        <dbl>   <dbl>   <dbl>
1 0610005C13Rik     1.54037 0.53120      0.00583      0.00899 5.49291 6.06505
2 0610007P14Rik     1.10976 0.00033     59.67286     66.22232 0.20263 0.28827
3 0610009B22Rik     0.78500 0.00000     83.28470     65.37819 0.17445 0.33958
4 0610009L18Rik     0.79852 0.00011      6.88321      5.49638 0.46288 0.53295
5 0610009O20Rik     0.91615 0.00387     14.67696     13.44630 0.25430 0.26679
6 0610010B08Rik     0.87931 0.01455      1.10363      0.97043 0.39564 0.52364

I'd like to round the floats (2nd columns onward) to 3 digits. What's the way to do it with dplyr::mutate_all()

我想将花车(第2列向前)绕到3位数。使用dplyr :: mutate_all()的方法是什么

I tried this:

我试过这个:

cols <- names(df)[2:7]
# df <- df %>% mutate_each_(funs(round(.,3)), cols)
# Warning message:
#'mutate_each_' is deprecated.
# Use 'mutate_all' instead.
# See help("Deprecated") 

df <- df %>% mutate_all(funs(round(.,3)), cols)

But get the following error:

但是得到以下错误:

Error in mutate_impl(.data, dots) : 
  3 arguments passed to 'round'which requires 1 or 2 arguments

1 个解决方案

#1

Try mutate_if with the added benefit of rounding columns iff it is numeric:

尝试使用mutate_if,如果它是数字,则可以使用舍入列的额外好处:

df %>% mutate_if(is.numeric, round, 3)

df%>%mutate_if(is.numeric,round,3)

Edited: simplified command (funs not needed) per @JdP advice

编辑:每个@JdP建议简化命令(不需要乐趣)

#1