1099. Build A Binary Search Tree (30)
A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than or equal to the node's key.
- Both the left and right subtrees must also be binary search trees.
Given the structure of a binary tree and a sequence of distinct integer keys, there is only one way to fill these keys into the tree so that the resulting tree satisfies the definition of a BST. You are supposed to output the level order traversal sequence of that tree. The sample is illustrated by Figure 1 and 2.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (<=100) which is the total number of nodes in the tree. The next N lines each contains the left and the right children of a node in the format "left_index right_index", provided that the nodes are numbered from 0 to N-1, and 0 is always the root. If one child is missing, then -1 will represent the NULL child pointer. Finally N distinct integer keys are given in the last line.
Output Specification:
For each test case, print in one line the level order traversal sequence of that tree. All the numbers must be separated by a space, with no extra space at the end of the line.
Sample Input:
9
1 6
2 3
-1 -1
-1 4
5 -1
-1 -1
7 -1
-1 8
-1 -1
73 45 11 58 82 25 67 38 42Sample Output:
58 25 82 11 38 67 45 73 42
思路
1.1064的老办法,将节点值升序排序后就是搜索树的中序遍历序列。
2.从根节点开始按中序遍历构造整棵树。
3.层次遍历打印整棵树(用队列BFS)。
代码
#include<iostream>
#include<vector>
#include<algorithm>
#include<queue>
using namespace std;
class Node
{
public:
int left;
int right;
int val;
};
vector<Node> bstnodes();
vector<int> nodevalue();
int index; void createBST(int root)
{
if(bstnodes[root].left != -)
createBST(bstnodes[root].left);
bstnodes[root].val = nodevalue[index++];
if(bstnodes[root].right != -)
createBST(bstnodes[root].right);
} int main()
{
int N;
while(cin >> N)
{
index = ;
for(int i = ;i < N;i++)
{
cin >> bstnodes[i].left >> bstnodes[i].right;
}
for(int i = ;i < N;i++)
{
cin >> nodevalue[i];
}
sort(nodevalue.begin(),nodevalue.begin()+N);
createBST(); //print
queue<int> q;
q.push();
while(!q.empty())
{
int temp = q.front();
q.pop();
if(temp != )
cout <<" ";
cout << bstnodes[temp].val;
if(bstnodes[temp].left != -)
q.push(bstnodes[temp].left);
if(bstnodes[temp].right != -)
q.push(bstnodes[temp].right);
}
cout << endl;
}
return ;
}