RDD join：加入两个不同的RDD后，生成的RDD键值和顺序发生了变化？

I have two pair RDDs let say

我说有两对RDD

 RDD1 : [(1,a),(2,b),(3,c)]    
 RDD2 : [(1,d),(2,e),(3,f)]

Now am joining these RDDs using join

现在我正在使用join加入这些RDD

 RDD3 = RDD1.join(RDD2);

And i have displayed the elements in RDD3 with below code

我已经在RDD3中显示了以下代码中的元素

 for(Tuple2<Integer,Tuple2<String,String>> tuple : RDD3.collect()) 
                      System.out.println(tuple._1()+":"+tuple._2()._1()+","+tuple._2()._2());

i have seen weird results like

我见过奇怪的结果

5:b,e
4:a,d 
6:c,f

where as i expected like

像我期望的那样

1:a,d
1:b,e 
1:c,f

Is there any way to get a desired output like the above ? or else am interpreting RDD behavior wrongly ? Please suggest

有没有办法像上面那样获得所需的输出?或者错误地解释RDD行为?请建议

Edit :

Actually i am reading data like this

其实我正在读这样的数据

JavaDoubleRDD data1 = sc.parallelizeDoubles(Arrays.asList(45.25,22.15,33.24));
JavaDoubleRDD data2 = sc.parallelizeDoubles(Arrays.asList(23.45,19.35,12.45));

and then

JavaPairRDD<Double,Double> lat1 = data1.cartesian(data1);
JavaRDD<Double> lat2 = lat1.map(new Function<Tuple2<Double,Double>,Double>() {
    @Override
    public Double call(Tuple2<Double,Double> t) {
        return Math.pow(t._1()-t._2(),2);
    }
});
 //flag and flag1 are static variables initially equal to 1
JavaPairRDD<Integer,Double> lat3 = lat2.mapToPair(new PairFunction<Double,Integer,Double>() {
    @Override
     public Tuple2<Integer,Double> call(Double d) {
        return new Tuple2<Integer,Double>(flag++,d);
    }
});
System.out.println("Latitude values display");  
    for(Tuple2<?,?> tuple : lat3.collect()) {
                  System.out.println(tuple._1()+":"+tuple._2());
    } 
JavaPairRDD<Double,Double> long1 = data2.cartesian(data2);
JavaRDD<Double> long2 = long1.map(new Function<Tuple2<Double,Double>,Double>() {
        @Override
        public Double call(Tuple2<Double,Double> t) {
                return Math.pow(t._1()-t._2(),2);
    }
});
    JavaPairRDD<Integer,Double> long3 = long2.mapToPair(new PairFunction<Double,Integer,Double>() {
        @Override
        public Tuple2<Integer,Double> call(Double d ) {
                return new Tuple2<Integer,Double>(flag1++,d);
        }
});
System.out.println("Longitude values display"); 
    for(Tuple2<?,?> tuple : long3.collect()) {
                  System.out.println(tuple._1()+":"+tuple._2());
    }
System.out.println("latitude and longitude values join");
JavaPairRDD<Integer,Tuple2<Double,Double>> weightmatrix1 = lat3.join(long3);
System.out.println("Weightmatrix1 Display");
    for(Tuple2<?,Tuple2<?,?>> tuple : weightmatrix1.collect()) {
                  System.out.println(tuple._1()+":"+tuple._2()._1()+","+tuple._2()._2());
    }

So what am doing is calculating weight matrix based on latitude and longitude values

那么我们正在做的是根据纬度和经度值计算权重矩阵

2 个解决方案

#1

When I do:

当我做:

scala> val rdd1 = sc.parallelize(Array((1,"a"),(2,"b"),(3,"c")))
scala> val rdd2 = sc.parallelize(Array((1,"d"),(2,"e"),(3,"f")))
scala> val rdd3 = rdd1.join(rdd2)
scala> rdd3.toArray.foreach(println(_))

I consistently get:

我一直得到:

(1,(a,d))
(2,(b,e))
(3,(c,f))

#2

That's what I tried with expected results:

这就是我尝试的预期结果:

val data1 = sc.parallelize(Array((1,"a"),(2,"b"),(3,"c")))
val data2 = sc.parallelize(Array((1,"d"),(2,"e"),(3,"f")))
val data3 = data1.join(data2)
data3.collect().map(tuple => tuple._1 + ":"+tuple._2._1+","+tuple._2._2).foreach(println(_))

Obtaining:

1:a,d
2:b,e
3:c,f

So this is scala. I suppose in Java should be the same output.

所以这是scala。我想在Java中应该是相同的输出。

#1