如何将A、B、C、D、E、F、G、H分开?

时间:2023-02-12 11:34:17

I want to split this String A,B,C,D,"E,F",G,H with comma(,) operator but not split the "E,F".. I want this following output.

我要把这个字符串分成A,B,C,D, E,F,G,H用逗号(,)运算符,但不拆分“E,F”我希望输出如下。

A
B
C
D
E,F
G
H

5 个解决方案

#1


0  

this may help:

这可以帮助:

    String s = "A,B,C,D,\"E,F\",G,H";
    String[] tmp = s.split(",\"|\",");
    List<String> result = new ArrayList<>();

    for(int i=0; i<tmp.length; i++) {
        if (i % 2 == 0) {
            result.addAll(Arrays.asList(tmp[i].split(",")));
        }else {
            result.add(tmp[i]);
        }
    }

The result list contains the elements

结果列表包含元素。

#2


0  

Here is an approach that does not use regexps:

这里有一个不使用regexp的方法:

private static List<String> splitQuoted(String string) {
    List<String> res = new ArrayList<>();
    int idx = 0;
    int start = 0;
    boolean inQuote = false;
    while (idx < string.length()) {
        char ch = string.charAt(idx++);
        if (ch == '"') {
            inQuote = !inQuote;
        } else {
            if (ch == ',' && !inQuote) {
                res.add(string.substring(start, idx - 1));
                start = idx;
            }
        }
    }
    if (start != idx)
        res.add(string.substring(start));
    return res;
}

It should scale well as the input string grows, since it only ever looks forward. You could improve upon its efficiency further by using char[] arrays instead of String.charAt(), too. It also leaves the quote characters in the output values, but it would be fairly trivial to remove them as you go.

它应该会随着输入字符串的增长而扩展,因为它只会期待。您可以通过使用char[]数组而不是String.charAt()来进一步提高它的效率。它还会在输出值中保留引号字符,但是在您离开时删除它们将是相当简单的。

#3


0  

This simple regex will match any string ending with a comma outside ": "([^\",]*\"[^\"]*\")*[^\",]*(,|$)", so you can split the string on comma or end string character matching the regex, like in this function:

这个简单的regex将匹配任何字符串以逗号结尾之外”:“([[^ ^ \”、\]*”\]* \”)*(^ \”)* | $(),这样你就可以用逗号或结束字符串的字符串来匹配正则表达式,比如在这个函数中:

private static List<String> splitByComma(String s) {
    List<String> output = new ArrayList<>();
    Pattern pattern = Pattern.compile("([^\",]*\"[^\"]*\")*[^\",]*(,|$)");
    Matcher matcher = pattern.matcher(s);
    while (matcher.find() && matcher.start() < s.length()) {
        output.add(s.substring(matcher.start(), (matcher.end() == s.length())?matcher.end():matcher.end() - 1));
    }
    return output;
}

#4


0  

regex to achieve expected results:

regex实现预期结果:

String stringToSearch = "A,B,C,D,\"E,F\",G,H";
Pattern p1 = Pattern.compile("(?:[^\",]+|\"[^\"]+\")+");
Matcher m = p1.matcher(stringToSearch);
while (m.find())
{   
    System.out.println(m.group());
}

#5


-3  

You can fix it by using replace();

您可以使用replace()来修复它;

String replaceString=s1.replace("\"","");//replaces all occurrences of "\"" to ""  

Then split .

然后分手。

#1


0  

this may help:

这可以帮助:

    String s = "A,B,C,D,\"E,F\",G,H";
    String[] tmp = s.split(",\"|\",");
    List<String> result = new ArrayList<>();

    for(int i=0; i<tmp.length; i++) {
        if (i % 2 == 0) {
            result.addAll(Arrays.asList(tmp[i].split(",")));
        }else {
            result.add(tmp[i]);
        }
    }

The result list contains the elements

结果列表包含元素。

#2


0  

Here is an approach that does not use regexps:

这里有一个不使用regexp的方法:

private static List<String> splitQuoted(String string) {
    List<String> res = new ArrayList<>();
    int idx = 0;
    int start = 0;
    boolean inQuote = false;
    while (idx < string.length()) {
        char ch = string.charAt(idx++);
        if (ch == '"') {
            inQuote = !inQuote;
        } else {
            if (ch == ',' && !inQuote) {
                res.add(string.substring(start, idx - 1));
                start = idx;
            }
        }
    }
    if (start != idx)
        res.add(string.substring(start));
    return res;
}

It should scale well as the input string grows, since it only ever looks forward. You could improve upon its efficiency further by using char[] arrays instead of String.charAt(), too. It also leaves the quote characters in the output values, but it would be fairly trivial to remove them as you go.

它应该会随着输入字符串的增长而扩展,因为它只会期待。您可以通过使用char[]数组而不是String.charAt()来进一步提高它的效率。它还会在输出值中保留引号字符,但是在您离开时删除它们将是相当简单的。

#3


0  

This simple regex will match any string ending with a comma outside ": "([^\",]*\"[^\"]*\")*[^\",]*(,|$)", so you can split the string on comma or end string character matching the regex, like in this function:

这个简单的regex将匹配任何字符串以逗号结尾之外”:“([[^ ^ \”、\]*”\]* \”)*(^ \”)* | $(),这样你就可以用逗号或结束字符串的字符串来匹配正则表达式,比如在这个函数中:

private static List<String> splitByComma(String s) {
    List<String> output = new ArrayList<>();
    Pattern pattern = Pattern.compile("([^\",]*\"[^\"]*\")*[^\",]*(,|$)");
    Matcher matcher = pattern.matcher(s);
    while (matcher.find() && matcher.start() < s.length()) {
        output.add(s.substring(matcher.start(), (matcher.end() == s.length())?matcher.end():matcher.end() - 1));
    }
    return output;
}

#4


0  

regex to achieve expected results:

regex实现预期结果:

String stringToSearch = "A,B,C,D,\"E,F\",G,H";
Pattern p1 = Pattern.compile("(?:[^\",]+|\"[^\"]+\")+");
Matcher m = p1.matcher(stringToSearch);
while (m.find())
{   
    System.out.println(m.group());
}

#5


-3  

You can fix it by using replace();

您可以使用replace()来修复它;

String replaceString=s1.replace("\"","");//replaces all occurrences of "\"" to ""  

Then split .

然后分手。