如何在django中的GET请求中存储URL参数？

I'm trying to capture tracking information from an external domain on my Django site. Clients on external domain load a js snippet:

我正在尝试从Django网站上的外部域捕获跟踪信息。外部域上的客户端加载了一个js片段：

(function() {
  var img = new Image,
      url = encodeURIComponent(document.location.href),
      title = encodeURIComponent(document.title),
      ref = encodeURIComponent(document.referrer);
  img.src = '%s/track.gif?url=' + url + '&t=' + title + '&ref=' + ref;
})();

That creates an image get request back to my server at /track.gif. How can I get my TrackView to treat the get request as a POST request and input the parameters into my database?

这会在/track.gif上创建一个图像获取请求回到我的服务器。如何让我的TrackView将get请求视为POST请求并将参数输入到我的数据库中？

Additional Info

附加信息

urls.py

urls.py

urlpatterns = patterns('',
    url(r'^browse_event$', BrowseEventView.as_view(), name='browse_event'),
    url(r'^cart_event$', CartEventView.as_view(), name='cart_event'),
    url(r'^product_view$', ProductView.as_view(), name='product_view'),
    url(r'^track.gif$', TrackView.as_view(), name='track_view'),
)

models.py

models.py

class Track(CommonDateTime, models.Model):
    domain = models.CharField(max_length=50)
    url_name = models.CharField(max_length=200)
    title = models.CharField(max_length=200)
    ip = models.CharField(max_length=200)
    referrer = models.CharField(max_length=200)

    class Meta:
        db_table = 'track_test'
        verbose_name = 'Tracking pixel test'
        verbose_name_plural = 'Tracking pixel tests'

forms.py

forms.py

class TrackForm(forms.Form):
    domain = forms.CharField()
    url_name = forms.CharField()
    title = forms.CharField()
    ip = forms.CharField()
    referrer = forms.CharFeld()

views.py

views.py

class TrackView(FormView):
    form_class = TrackForm
    success_url = '/'

    def form_valid(self, form):
        try:
            track = Track.objects.get(domain = form.cleaned_data['domain'])
            track.url_name = form.cleaned_data['url']
            track.title = form.cleaned_data['title']
            track.ip = form.cleaned_data['ip']
            track.referrer = form.cleaned_data['referrer']
            track.save()
        except Track.DoesNotExist:
            track = Track(
                        domain = form.cleaned_data['domain']
                        url_name = form.cleaned_data['url']
                        title = form.cleaned_data['title']
                        ip = form.cleaned_data['ip']
                        referrer = form.cleaned_data['referrer']
                      )
            track.save()
        return super(TrackView, self).form_valid(form)

1 个解决方案

#1

why do you need POST request? Just implement the GET request using simple get() - class view of function.

为什么你需要POST请求？只需使用简单的get（） - 类函数视图实现GET请求。

You can just use check query request.GET directly, or if you want to use form, you can just instantiate it with the request.GET as the parameter, but IMHO, there is no real reason for this.

您可以直接使用check query request.GET，或者如果您想使用表单，您可以使用request.GET作为参数实例化它，但是恕我直言，没有真正的原因。

You can just do something like this:

你可以这样做：

class TrackView(View):
    def get(self, request):
        try:
            track,_ = Track.objects.get_or_create(domain = request.GET['domain'])
            track.url_name = request.GET['url']
            track.title = request.GET['title']
            track.ip = request.GET['ip']
            track.referrer = request.GET['referrer']
            track.save()
            return HttpResponse(status=200) 
        except KeyError:
            return HttpResponse(status=400)

#1