如何一次更新具有相同值的多行和数据库? Laravel

时间:2022-12-02 17:18:44

I'm stuck in code. I managed to create a form that adds a multiple number of rows in db but I do not know how to update them at the same time when i need to use product_code as id.

我陷入了代码困境。我设法创建一个在db中添加多个行的表单但我不知道如何在我需要使用product_code作为id的同时更新它们。

This is table 1 (products) structure:

这是表1(产品)结构:

id | product_name | product_code
1  | Name1        | 101
2  | Name2        | 102
3  | Name3        | 103
4  | Name4        | 104

This is table 2 (products_ing) structure:

这是表2(products_ing)结构:

id | product_code | ing_name  | ing_weight
1  | 101          | INGName1  | 110
2  | 101          | INGName2  | 10
3  | 101          | INGName3  | 54
4  | 101          | INGName4  | 248

This is edit function:

这是编辑功能:

    public function post_edit($id = null)
{

    if(Input::get('submit'))
    {
        // ID
        if($id !== null)
        {
            $id = trim(filter_var($id, FILTER_SANITIZE_NUMBER_INT));
        }


        $input = Input::all();

        $validation = Validator::make($input);

        else
        {
            foreach ($input as $key => $value)
            {
                $input[$key] = ($value !== '') ? trim(filter_var($value, FILTER_SANITIZE_STRING)) : null;
            }

            try
            {

                DB::table('products')
                    ->whereIn($id)
                    ->update(array(
            'product_name'          => $items['product_name'],
            'product_code'          => $items['product_code']
                ));


            }

    }

    return $this->get_edit($id);
}

With this I can only edit *product_name* and product_code from products table by id. But I'm trying to update multiple rows from db with same product_code that would serve as id.

有了这个,我只能通过id编辑产品表中的* product_name *和product_code。但我正在尝试使用相同的product_code更新db中的多行,这些行将作为id。

// I found on Google images one good image that explains what I'm trying to do but with Laravel:

//我在Google图片上找到了一个很好的图像,它解释了我正在尝试做的事情,但是使用Laravel:

IMAGE LINK

图片链接

Is there a solution? Thank you in advance!

有解决方案吗?先谢谢你!

1 个解决方案

#1


0  

Assuming you are using MySQL: Let the database's foreign key do this for you, with the ON UPDATE CASCADE command. This will update all referenced tables if you change the product_code in your base products table.

假设您正在使用MySQL:让数据库的外键使用ON UPDATE CASCADE命令为您执行此操作。如果更改基础产品表中的product_code,这将更新所有引用的表。

CREATE-Script of products_ing

CREATE-产品脚本_ing

...
product_code INT NOT NULL REFERENCES products(product_code) ON UPDATE CASCADE
...

As laravel migration

作为laravel迁移

Schema::create('products_ing', function($table) {
    $table->increments('id');
    $table->int('product_code');
    $table->string('ing_name');
    $table->int('ing_weight');

    /* All the other key stuff */
    $table
        ->foreign('product_code')
        ->references('product_code')
        ->on('products')
        ->onUpdate('cascade');
});

#1


0  

Assuming you are using MySQL: Let the database's foreign key do this for you, with the ON UPDATE CASCADE command. This will update all referenced tables if you change the product_code in your base products table.

假设您正在使用MySQL:让数据库的外键使用ON UPDATE CASCADE命令为您执行此操作。如果更改基础产品表中的product_code,这将更新所有引用的表。

CREATE-Script of products_ing

CREATE-产品脚本_ing

...
product_code INT NOT NULL REFERENCES products(product_code) ON UPDATE CASCADE
...

As laravel migration

作为laravel迁移

Schema::create('products_ing', function($table) {
    $table->increments('id');
    $table->int('product_code');
    $table->string('ing_name');
    $table->int('ing_weight');

    /* All the other key stuff */
    $table
        ->foreign('product_code')
        ->references('product_code')
        ->on('products')
        ->onUpdate('cascade');
});