jquery选择器，用于未禁用的所有选中复选框

how can I find all checkboxes, that are checked and not disabled?

如何找到所有已选中且未禁用的复选框?

5 个解决方案

#1

$('input[type="checkbox"]').filter(function() {
return !this.disabled && this.checked;
})

#2

Like so:

$("input[type='checkbox']:checked").not(":disabled")...

This finds fields that are inputs, with type checkbox, which are checked, and not disabled. If this does not work, you should use an attribute check:

这将查找输入的字段,其类型为复选框,已选中且未禁用。如果这不起作用,您应该使用属性检查:

$("input[type='checkbox']:checked").not("[disabled]")...

Or, as @lonesomeday astutely pointed out, you can combine it into one selector:

或者,正如@lonesomeday精明地指出的那样,你可以将它组合成一个选择器:

$("input[type='checkbox']:checked:not(:disabled)")...

I've put together a proof-of-concept in this fiddle.

我在这个小提琴中整理了一个概念验证。

#3

$('input[type="checkbox"]:checked').not(":disabled");

Here's a fiddle

这是一个小提琴

#4

You can use this selector..

你可以使用这个选择器..

$('input[type=checkbox]:checked:not(:disabled)')

Check This FIDDLE

检查这个FIDDLE

#5

how about $("input[type='checkbox']:checked:enabled") ?

怎么样$(“input [type ='checkbox']:选中:启用”)?

#1

$('input[type="checkbox"]').filter(function() {
return !this.disabled && this.checked;
})

#2