如何使用Python获取当前文件，当前类和当前方法？

Name of the file from where code is running

运行代码的文件的名称

Name of the class from where code is running

运行代码的类的名称

Name of the method (attribute of the class) where code is running

代码运行的方法的名称(类的属性)

4 个解决方案

#1

Here is an example of each:

以下是每个例子:

from inspect import stack

class Foo:
    def __init__(self):
        print __file__
        print self.__class__.__name__
        print stack()[0][3]

f = Foo()

#2

import sys

class A:
    def __init__(self):
        print __file__
        print self.__class__.__name__
        print sys._getframe().f_code.co_name

a = A()

#3

self.__class__.__name__  # name of class i'm in

for the rest the sys and trace modules

其余的sys和跟踪模块

http://docs.python.org/library/sys.html http://docs.python.org/library/trace.html

Some more info: https://mail.python.org/pipermail/python-list/2001-August/096499.html and http://www.dalkescientific.com/writings/diary/archive/2005/04/20/tracing_python_code.html

更多信息:https://mail.python.org/pipermail/python-list/2001-August/096499.html和http://www.dalkescientific.com/writingings/diary/archive/2005/04/20/ tracing_python_code.html

did you want it for error reporting because the traceback module can handle that:

你想要它用于错误报告吗,因为回溯模块可以处理:

http://docs.python.org/library/traceback.html

#4

Be very careful. Consider:

要特别小心。考虑:

class A:
    pass

B = A
b = B()

What is the 'class name' of b here? Is it A, or B? Why?

这里b的'类名'是什么?是A还是B?为什么?

The point is, you shouldn't need to know or care. An object is what it is: its name is very rarely useful.

关键是,你不应该知道或关心。对象就是这样的:它的名字很少有用。

#1