【LeetCode】Minimum Depth of Binary Tree 二叉树的最小深度 java

时间:2023-12-22 15:28:50

【LeetCode】Minimum Depth of Binary Tree

Given a binary tree, find its minimum depth.

The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.

递归和非递归,此提比较简单。广度优先遍历即可。关键之处就在于如何保持访问深度。

下面是4种代码:

 import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List;
import java.util.Queue; class TreeNode {
int val;
TreeNode left;
TreeNode right; TreeNode(int x) {
val = x;
}
}
public class MinimumDepthofBinaryTree {
/**
* 递归深度遍历
* @param root
* @return
*/
public int minDepth1(TreeNode root) {
if(root==null)
return 0;
if(root.left==null&&root.right==null){
return 1;
}
int left=minDepth1(root.left);
int right=minDepth1(root.right);
if(left==0){
return right+1;
}
if(right==0){
return left+1;
}
else{
return Math.min(right, left)+1;
}
}
public int minDepth2(TreeNode root) {
if(root==null)
return 0;
int left=minDepth1(root.left);
int right=minDepth1(root.right); if(left==0&&right==0){
return 1;
}
if(left==0){
right= Integer.MAX_VALUE;
}
if(right==0){
left=Integer.MAX_VALUE;
} return Math.min(right, left)+1; } /**
* 广度优先搜索。一旦发现叶子结点,返回遍历深度。
* @param root
* @return
*/
public int minDepth3(TreeNode root) {
if(root==null){
return 0;
}
Queue<TreeNode>queue=new LinkedList<>();
queue.add(root);
int count=queue.size();//用来保存访问当前层次剩余未访问的节点。
int depth=1;//用来保存二叉树的访问深度
while(!queue.isEmpty()){
//广度遍历
TreeNode topNode=queue.poll();
count--;
if(topNode.left!=null){
queue.add(topNode.left);
}
if(topNode.right!=null){
queue.add(topNode.right);
}
//发现叶子节点
if(topNode.left==null&&topNode.right==null){
return depth;
}
//访问一层完毕
if(count==0){
depth++;
count=queue.size();
} }
return 0;
}
/**
* 广度优先搜索。一旦发现叶子结点,返回遍历深度。
* @param root
* @return
*/
public int minDepth4(TreeNode root) {
if(root==null){
return 0;
}
List<TreeNode>list=new ArrayList<>();
int count=1;
list.add(root);
while(list.size()!=0){
List<TreeNode>singleList=new ArrayList<>();
for(TreeNode t:list){
if(t.left!=null){
singleList.add(t.left);
}if(t.right!=null){
singleList.add(t.right);
}
if(t.left==null&&t.right==null){
return count;
}
}
count++;
list=singleList;
}
return 0;
}
public static void main(String[] args) {
TreeNode rootNode1 = new TreeNode(1);
TreeNode rootNode2 = new TreeNode(2);
TreeNode rootNode3 = new TreeNode(3);
TreeNode rootNode4 = new TreeNode(4);
TreeNode rootNode5 = new TreeNode(5);
TreeNode rootNode6 = new TreeNode(6);
TreeNode rootNode7 = new TreeNode(7);
rootNode1.left = rootNode2;
rootNode1.right = rootNode3;
rootNode2.left = rootNode4;
rootNode2.right = rootNode5;
rootNode3.left = rootNode6;
rootNode3.right = rootNode7;
MinimumDepthofBinaryTree minimumDepthofBinaryTree=new MinimumDepthofBinaryTree();
System.out.println(minimumDepthofBinaryTree.minDepth4(rootNode1)); } }