在ajax调用后成功返回后提交表单

时间:2022-10-08 08:33:37

I validate my form with both client and sever side scripting. First I validate it with jQuery then it goes to php validation and if it returns success or something like that I want to submit the form but some how the condition does not work. However in html err_msg I get success text but its not working.

我使用客户端和服务器端脚本验证我的表单。首先我用jQuery验证它,然后它进入php验证,如果它返回成功或类似的东西,我想提交表单,但有些条件如何不起作用。但是在html err_msg中我获得了成功文本,但它不起作用。

jQuery.validator.setDefaults({
    submitHandler: function () {
        var name = $na('#inf_field_FirstName').val();
        var password = $na('#inf_field_Password').val();
        var cpass = $na('#cpass').val();
        var email = $na('#inf_field_Email').val();
        var age = $na('#inf_custom_Age').val();
        $na.ajax({
            type: "POST",
            url: '<?php bloginfo('
            template_url ')?>/user_create.php',
            data: 'name=' + name + '&email=' + email + '&password=' + password + '&cpass=' + cpass + '&age=' + age,
            cache: false,
            success: function (result) {
                jQuery('.err_msg').html(result);
                if (jQuery('.err_msg').html == 'sucess') {
                    jQuery("#inform").submit();
                } else {
                    alert('error');
                }
            }
        });
    }
});

1 个解决方案

#1


0  

use jQuery("#inform")[0].submit();

otherwise, if u have submit button in your form just trigger that button

否则,如果您在表单中有提交按钮,则只需触发该按钮

jQuery("#submit_btn_id").trigger('click')

#1


0  

use jQuery("#inform")[0].submit();

otherwise, if u have submit button in your form just trigger that button

否则,如果您在表单中有提交按钮,则只需触发该按钮

jQuery("#submit_btn_id").trigger('click')