I have a menu, it contains multiple items, each menu item will retrieve data from the database. I want to do it without the page refresh, I want like an area that will change when the user clicks on the menu link. How should I send data to the php script and how should I get it from there and preview it on the page? If you can send me any information, references or examples that will be great. Thanks in advance.
我有一个菜单，它包含多个项目，每个菜单项将从数据库中检索数据。我想在没有页面刷新的情况下这样做，我想要一个在用户点击菜单链接时会改变的区域。我应该如何将数据发送到PHP脚本，我应该如何从那里获取并在页面上预览？如果您能向我发送任何信息，参考或示例，那将是很棒的。提前致谢。
1 个解决方案
#1
1
I would start by reading some of the documentation from the jQuery website: http://api.jquery.com/category/ajax/
我将首先阅读jQuery网站上的一些文档：http：//api.jquery.com/category/ajax/
This might also be of interest to you: http://articles.sitepoint.com/article/ajax-jquery
您可能也对此感兴趣：http：//articles.sitepoint.com/article/ajax-jquery
#1
1
I would start by reading some of the documentation from the jQuery website: http://api.jquery.com/category/ajax/
我将首先阅读jQuery网站上的一些文档：http：//api.jquery.com/category/ajax/
This might also be of interest to you: http://articles.sitepoint.com/article/ajax-jquery
您可能也对此感兴趣：http：//articles.sitepoint.com/article/ajax-jquery