来自MySQL的PHP​​显示图像BLOB [复制]

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• How to retrieve images from MySQL database and display in an html tag 5 answers
• 如何从MySQL数据库中检索图像并在html标签中显示5个答案

I'm attempting to display an image stored in the BLOB column in the database;

我正在尝试显示存储在数据库中BLOB列中的图像;

I fetch the data from the database with a SELECT perform no transformations on the data and display it with the following (from a script whose only output is the following):

我从数据库中获取数据，使用SELECT对数据执行无变换，并使用以下内容显示它（来自脚本，其唯一输出如下）：

header("Content-Type: image/jpeg");
echo $image;

Please note chrome is displaying the content size as the correct size for the image as well as the correct mime type (image/jpeg). nothing is echoing out before the header and ive checked the blob in the database is correct. There is also no trailing whitespace before or after the <?php ?> tags.

请注意，chrome将内容大小显示为图像的正确大小以及正确的mime类型（image / jpeg）。在标题之前没有任何回声，我已经检查了数据库中的blob是否正确。在<？php？>标记之前或之后也没有尾随空格。

chrome/IE displays an image icon but not the image itself. any ideas?

chrome / IE显示图像图标但不显示图像本身。有任何想法吗？

EDIT: image is got the from the database as such:

编辑：图像是从数据库中得到的：

$sql = "SELECT * FROM products WHERE id = $id";
$sth = $db->query($sql);
$row = $sth->fetch();
$image = $row['image'];

var_dump($image) gives:

var_dump（$ image）给出：

string 'ÿØÿà�JFIF��x�x��ÿá�ZExif��MM�*�����������J��������Q�������Q������tQ������t�����† ��±ÿÛ�C�       

ÿÛ�CÿÀ�_"�ÿÄ����������� 
ÿÄ�µ���}�!1AQa"q2‘¡#B±ÁRÑð$3br‚ 
%&'()*456789:CDEFGHIJSTUVWXYZcdefghijstuvwxyzƒ„…†‡ˆ‰Š’“”•–—˜™š¢£¤¥¦§¨©ª²³    ´µ¶·¸¹ºÂÃÄÅÆÇÈÉÊÒÓÔÕÖ×ØÙÚáâãäåæçèéêñòóôõö÷øùúÿÄ��������'... (length=60766)

3 个解决方案

#1

Try Like this.

试试这样。

For Inserting into DB

用于插入DB

$db = mysqli_connect("localhost","root","","DbName"); //keep your db name
$image = addslashes(file_get_contents($_FILES['images']['tmp_name']));
//you keep your column name setting for insertion. I keep image type Blob.
$query = "INSERT INTO products (id,image) VALUES('','$image')";  
$qry = mysqli_query($db, $query);

For Accessing image From Blob

用于从Blob访问图像

$db = mysqli_connect("localhost","root","","DbName"); //keep your db name
$sql = "SELECT * FROM products WHERE id = $id";
$sth = $db->query($sql);
$result=mysqli_fetch_array($sth);
echo '<img src="data:image/jpeg;base64,'.base64_encode( $result['image'] ).'"/>';

Hope It will help you.

希望它会帮助你。

Thanks.

谢谢。

#2

This is what I use to display images from blob:

这是我用来显示blob图像的方法：

echo '<img src="data:image/jpeg;base64,'.base64_encode($image->load()) .'" />';

#3

Since I have to store varius types of content in my blob field/column, suppose to update my code like this:

因为我必须在我的blob字段/列中存储varius类型的内容，所以假设更新我的代码，如下所示：

echo "data: $mime" $result['$data']";

where: mime can be an image of any kind, text, word document, text document, pdf document, e.t.c... data is blob's column content

其中：mime可以是任何类型的图像，文本，word文档，文本文档，pdf文档，e.t.c ...数据是blob的列内容