PHP实现简单注册登录详细代码

时间:2022-09-24 18:52:26

PHP实现简单注册登录 详细全部代码 先看演示~

示例图:


PHP实现简单注册登录详细代码

PHP实现简单注册登录详细代码

Ps.本人有点懒哈~ 就输出个成功算了吧~

PHP实现简单注册登录详细代码

PHP实现登录注册

  • index.php (首页)
  • login.php (登录)
  • register.php (注册)

代码里面注释写很详细了哦~ 废话不多说 直接上代码~

index.php文件

代码如下:

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<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<title>Zhe - 注册登录</title>
<link rel="stylesheet" type="text/css" href="https://www.layuicdn.com/layui/css/layui.css" rel="external nofollow" />
<script src="https://www.layuicdn.com/layui/layui.js" charset="utf-8"></script>
</head>
<body>
<fieldset class="layui-elem-field layui-field-title" style="margin-top: 20px;">
 <legend>Zhe - 登录注册演示</legend>
</fieldset>
<div style="padding: 20px; background-color: #F2F2F2;">
 <div class="layui-row layui-col-space15">
 <div class="layui-col-md6">
  <div class="layui-card">
  <div class="layui-card-header">注册</div>
  <div class="layui-card-body">
            <form class="layui-form" action="register.php" method="post" onsubmit="return checkForm(this)" lay-filter="example">
             <div class="layui-form-item">
             <label class="layui-form-label">输入框</label>
             <div class="layui-input-block">
              <input type="text" name="username" placeholder="请输入账号" class="layui-input">
             </div>
             </div>
             <div class="layui-form-item">
             <label class="layui-form-label">密码框</label>
             <div class="layui-input-block">
              <input type="password" name="password" placeholder="请输入密码" class="layui-input">
             </div>
             </div>           
             <div class="layui-form-item">
             <div class="layui-input-block">
              <input type="submit" class="layui-btn layui-btn-normal" value="立即注册"/>
             </div>
             </div>
            </form>
  </div>
  </div>
 </div>
 <div class="layui-col-md6">
  <div class="layui-card">
  <div class="layui-card-header">登录</div>
  <div class="layui-card-body">
            <form class="layui-form" action="login.php" method="post" onsubmit="return checkForm(this)" lay-filter="example">
             <div class="layui-form-item">
             <label class="layui-form-label">输入框</label>
             <div class="layui-input-block">
              <input type="text" name="username" placeholder="请输入账号" class="layui-input">
             </div>
             </div>
             <div class="layui-form-item">
             <label class="layui-form-label">密码框</label>
             <div class="layui-input-block">
              <input type="password" name="password" placeholder="请输入密码" class="layui-input">
             </div>
             </div>           
             <div class="layui-form-item">
             <div class="layui-input-block">
                 <input type="submit" class="layui-btn layui-btn-normal" value="立即登录"/>
             </div>
             </div>
            </form>
  </div>
  </div>
 </div>
 </div>
</div>
<script type="text/javascript">
    // 验证输入不为空的脚本代码
    function checkForm(form) {
    if(form.username.value == "") {
    alert("用户名不能为空!");
    form.username.focus();
    return false;
    }
    if(form.password.value == "") {
    alert("密码不能为空!");
    form.password.focus();
    return false;
    }
    return true;
    }
</script>
</body>
</html>

login.php文件

代码如下:

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<?php
    session_start();
    header("content-type:text/html;charset=utf-8");
    //连接数据库
    $link = mysqli_connect("localhost","pay_com_cn","pay_com_cn","pay_com_cn");
    if (!$link) {
        die("连接失败: " . mysqli_connect_error());
    }
    //接收$_POST用户名和密码
    $username = $_POST['username'];
    $password = $_POST['password'];
    //查看表user用户名与密码和传输值是否相等
    $sql = "SELECT * FROM user WHERE username = '$username' AND password = '$password'";
    //result必需规定由 mysqli_query()、mysqli_store_result() 或 mysqli_use_result() 返回的结果集标识符。
    $result = mysqli_query($link,$sql);
    $num = mysqli_num_rows($result);//函数返回结果集中行的数量
    //判断是否登录后显示或跳转
    if($num){
        echo '登录成功';
    }else{
        echo'登录失败';
    }
    mysqli_close($link);//关闭数据库
 ?>

register.php文件

代码如下:

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<?php
    header("content-type:text/html;charset=utf-8");
    //连接数据库
    $link = mysqli_connect("localhost","pay_com_cn","pay_com_cn","pay_com_cn");
    if (!$link) {
        die("连接失败: " . mysqli_connect_error());
    }
    //接收$_POST用户名和密码
    $username=$_POST['username'];
    $password=$_POST['password'];
    //查看表user用户名是否存在或为空
    $sql_select = "SELECT * FROM user WHERE username = '$username'";
    //result必需规定由 mysqli_query()、mysqli_store_result() 或 mysqli_use_result() 返回的结果集标识符。
    $select = mysqli_query($link,$sql_select);
    $num = mysqli_num_rows($select);//函数返回结果集中行的数量
    if($username == "" || $password == "")
    {
        echo "请确认信息完整性";
    }else if($num){
        echo "已存在用户名";//已存在账户名输出错误
    }else{
            $sql="insert into user(username,password) values('$username','$password')";
            $result=mysqli_query($link,$sql);
            //判断是否注册后显示内容
            if(!$result)
            {
                echo "注册不成功!"."<br>";//输出错误
                echo "<a href='index.php'>返回</a>";//超链接到首页
            }
            else
            {
                echo "注册成功!"."<br/>";//输出成功
                echo "<a href='index.hphp'>立刻登录</a>";//超链接到首页
            }
        }
    
?>

最后附上本文用到的mysql表

注意先将数据库和user表字段创建完成在运行程序

PHP实现简单注册登录详细代码

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原文链接:https://blog.csdn.net/weixin_45561522/article/details/111144973