php利用嵌套数组拼接与解析json的方法

时间:2022-09-23 22:03:31

利用嵌套数组   拼接混合json -包含对象数组

php" id="highlighter_638285">
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<?php
 
// 自 PHP 5.4 起
$array = [
  "status" => "0",
  "message" => "ok",
  "arr"=> []
];
 
class Person { 
  public $name
  public $age
  
  //定义一个构造方法初始化赋值 
  public function __construct($name,$age) { 
    $this->name=$name
    $this->age=$age
  
  
  
 
for($i=0;$i<10;$i++)
{
  $p=new Person("ren",$i); 
  $array["arr"][]=$p;
}
 
//var_dump($array);
 
echo json_encode($array);
 
?>

php利用嵌套数组  解析混合json  包含对象数组

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<?php 
function json_to_array($web) { 
  $arr=array(); 
  foreach($web as $k=>$v) { 
    if(is_object($v)) $arr[$k]=json_to_array($v); //判断类型是不是object 
    else $arr[$k]=$v
  
  return $arr
$s='{"webname":"homehf","url":"www.homehf.com","qq":"744348666"}'
//将字符转成JSON 
$web=json_decode($s); 
$arr=array(); 
foreach($web as $k=>$v
  $arr[$k]=$v
echo "<pre>"
print_r($arr); 
echo "</pre>"
  
$s='{"webname":"homehf","url":"www.homehf.com","contact":{"qq":"744348666","mail":"nieweihf@163.com","xx":"xxxxxxx"}}'
$web=json_decode($s); 
$arr=json_to_array($web); 
echo "<pre>"
print_r($arr); 
echo "</pre>"
  
/************************************************************************
************************************************************************/
$s='{"webname":"homehf","url":"www.homehf.com","contact":{"qq":"744348666","mail":"nieweihf@163.com","xx":"xxxxxxx"}}'
$web=json_decode($s); 
echo '网站名称:'.$web->webname.'<br />网址:'.$web->url.'<br />联系方式:QQ-'.$web->contact->qq.' MAIL:'.$web->contact->mail; 
echo '<br /><br />'
/************************************************************************
************************************************************************/
$s='{"webname":"homehf","url":"www.homehf.com","contact":{"qq":"744348666","mail":"nieweihf@163.com","xx":"xxxxxxx"}}'
$web=json_decode($s); 
echo json_encode($web); 
 
 
$mys='{"status":"0","message":"ok","arr":[{"name":"ren","age":0},{"name":"ren","age":1},{"name":"ren","age":2},
{"name":"ren","age":3},{"name":"ren","age":4},{"name":"ren","age":5},{"name":"ren","age":6},{"name":"ren","age":7},
{"name":"ren","age":8},{"name":"ren","age":9}]}';
 
$myweb=json_decode($mys); 
 
echo $myweb->status;
 
for($i=0;$i<10;$i++)
{
 echo $myweb->arr[$i]->age;
 echo '<br /><br />'
?>

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原文链接:http://blog.csdn.net/bfboys/article/details/53767233