I have a table called "actions" with a DATETIME column called "occurred". I'm trying to return the records for today by doing the following
我有一个名为“actions”的表，其中有一个名为“occurrence”的DATETIME列。我正在尝试通过执行以下操作返回今天的记录
SELECT * FROM `actions` WHERE `occurred` = DATE(NOW());
But I get an empty result set. If I take the WHERE clause out, I can see all 295 rows in the table and there's at least 30 rows from today. Later I will be writing another query to return all records between today's date and X amount of days in the past but before I can get there I need to know why this query is returning an empty result set.
但我得到一个空的结果集。如果我取出WHERE子句，我可以看到表中的所有295行，并且从今天开始至少有30行。稍后我将编写另一个查询来返回今天的日期和过去的X天数之间的所有记录，但在我到达那里之前，我需要知道为什么这个查询返回一个空的结果集。
Thanks in advance.
提前致谢。
2 个解决方案
#1
4
If there in no future date in occurred, you could just use below:
如果未来的日期没有发生，您可以在下面使用：
SELECT * FROM `actions` WHERE `occurred` > DATE_SUB(CURDATE(), INTERVAL 1 DAY);
#2
7
SELECT * FROM actions WHERE DATE(ocurred) = CURDATE();
DATE(ocurred) ignores the time part.
DATE（ocurred）忽略了时间部分。
Here's the SQL Fiddle to play with the data: http://www.sqlfiddle.com/#!2/81708/2
以下是使用数据的SQL小提琴：http：//www.sqlfiddle.com/#！2/81708/2
#1
4
If there in no future date in occurred, you could just use below:
如果未来的日期没有发生，您可以在下面使用：
SELECT * FROM `actions` WHERE `occurred` > DATE_SUB(CURDATE(), INTERVAL 1 DAY);
#2
7
SELECT * FROM actions WHERE DATE(ocurred) = CURDATE();
DATE(ocurred) ignores the time part.
DATE（ocurred）忽略了时间部分。
Here's the SQL Fiddle to play with the data: http://www.sqlfiddle.com/#!2/81708/2
以下是使用数据的SQL小提琴：http：//www.sqlfiddle.com/#！2/81708/2