I have a string $newAfter that outputs like Wednesday 9th of March 2016 11:59:59 PM.
我有一个字符串$ newAfter输出像2016年3月9日星期三晚上11:59:59。
I use this code to calculate the days left:
我使用此代码计算剩余的天数:
$daysleft = floor(($newAfter - time()) / 86400);
this is the result I get:
这是我得到的结果:
-16559
I want the days remaining up leading up to the date in string.
我希望剩下的日子一直持续到字符串中的日期。
1 个解决方案
#1
Of course you can't subtract days from that format string, you'll need to subtract them as integers of use DateTime objects:
当然你不能从那个格式字符串中减去天数,你需要将它们减去为使用DateTime对象的整数:
$notAfter = 'Thu, 28 Apr 2016 03:22:56 +0200';
$today = new DateTime;
$date = DateTime::createFromFormat('D, d M Y H:i:s O', $notAfter);
$diff = $date->diff($today);
echo "{$diff->days} days left.";
#1
Of course you can't subtract days from that format string, you'll need to subtract them as integers of use DateTime objects:
当然你不能从那个格式字符串中减去天数,你需要将它们减去为使用DateTime对象的整数:
$notAfter = 'Thu, 28 Apr 2016 03:22:56 +0200';
$today = new DateTime;
$date = DateTime::createFromFormat('D, d M Y H:i:s O', $notAfter);
$diff = $date->diff($today);
echo "{$diff->days} days left.";