黄瓜/水豚:检查一页没有内容?

Using Cucumber and Capybara, is there a way to verify that a string is NOT present on a page?

使用Cucumber和Capybara，是否有一种方法来验证一个字符串是否存在于页面上?

For example, how would I write the opposite of this step:

例如，我该如何写这一步的反义词:

Then /^I should see "(.*?)"$/ do |arg1|
  page.should have_content(arg1)
end

This passes if arg1 is present.

如果arg1存在，则通过。

How would I write a step that fails if arg1 is found?

如果发现arg1，我该如何编写一个失败的步骤?

5 个解决方案

#1

http://rubydoc.info/github/jnicklas/capybara/master/Capybara/Node/Matchers#has_no_text%3F-instance_method

http://rubydoc.info/github/jnicklas/capybara/master/Capybara/Node/Matchers has_no_text f-instance_method % 3

There is a has_no_content matcher in Capybara. So you can write

在Capybara有一个has_no_content matcher。所以你可以写

  Then /^I should not see "(.*?)"$/ do |arg1|
    page.should have_no_content(arg1)
  end

#2

In Rspec 3.4 currently (2016) this is the recommended way to test for not having content:

在Rspec 3.4当前(2016)中，这是测试没有内容的推荐方法:

expect(page).not_to have_content(arg1)

#3

You can also use should_not if you want it read a little better:

如果你想让它读得更好一些，你也可以使用should_not:

Then /^I should not see "(.*?)"$/ do |arg1|
  page.should_not have_content(arg1)
end

Some more info: https://www.relishapp.com/rspec/rspec-expectations/docs

更多信息:https://www.relishapp.com/rspec/rspec-expectations/docs

#4

currently, you can use:

现在,您可以使用:

Then /^I not see "(.*?)"$/ do |arg1|
  expect(page).to have_no_content(arg1)
end

And if the content is found in the page, your test is red

如果在页面中找到内容，您的测试是红色的

#5

Oh, wait, I figured it out. This works:

等等，我想出来了。如此:

Then /^I should see "(.*?)"$/ do |arg1|
  page.has_content?(arg1) == false
end