如何从地址中找到经度和纬度?

时间:2022-02-13 08:04:15

I want to show the location of an address in Google Maps.

我想在Google地图中显示地址的位置。

How do I get the latitude and longitude of an address using the Google Maps API?

如何使用Google Maps API获取地址的纬度和经度?

7 个解决方案

#1


119  

public GeoPoint getLocationFromAddress(String strAddress){

Geocoder coder = new Geocoder(this);
List<Address> address;
GeoPoint p1 = null;

try {
    address = coder.getFromLocationName(strAddress,5);
    if (address==null) {
       return null;
    }
    Address location=address.get(0);
    location.getLatitude();
    location.getLongitude();

    p1 = new GeoPoint((double) (location.getLatitude() * 1E6),
                      (double) (location.getLongitude() * 1E6));

    return p1;
    }
}

strAddress is a string containing the address. The address variable holds the converted addresses.

strAddress是包含地址的字符串。地址变量保存转换后的地址。

#2


58  

Ud_an's solution with updated API's

Ud_an的解决方案包含更新的API

Note: LatLng class is part of Google Play Services.

注意:LatLng类是Google Play服务的一部分。

Mandatory:

强制性:

<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>

<uses-permission android:name="android.permission.INTERNET"/>

Update: If you have target SDK 23 and above, make sure you take care of runtime permission for location.

更新:如果您有目标SDK 23及更高版本,请确保您负责位置的运行时权限。

public LatLng getLocationFromAddress(Context context,String strAddress) {

    Geocoder coder = new Geocoder(context);
    List<Address> address;
    LatLng p1 = null;

    try {
        // May throw an IOException
        address = coder.getFromLocationName(strAddress, 5);
        if (address == null) {
            return null;
        }

        Address location = address.get(0);
        p1 = new LatLng(location.getLatitude(), location.getLongitude() );

    } catch (IOException ex) {

        ex.printStackTrace();
    }

    return p1;
}

#3


51  

If you want to place your address in google map then easy way to use following

如果您想将地址放在谷歌地图中,​​那么可以轻松使用以下内容

Intent searchAddress = new  Intent(Intent.ACTION_VIEW,Uri.parse("geo:0,0?q="+address));
startActivity(searchAddress);

OR

要么

if you needed to get lat long from your address then use Google Place Api following

如果您需要从您的地址获得很长的时间,请使用Google Place Api

create a method that returns a JSONObject with the response of the HTTP Call like following

创建一个方法,返回带有HTTP调用响应的JSONObject,如下所示

public static JSONObject getLocationInfo(String address) {
        StringBuilder stringBuilder = new StringBuilder();
        try {

        address = address.replaceAll(" ","%20");    

        HttpPost httppost = new HttpPost("http://maps.google.com/maps/api/geocode/json?address=" + address + "&sensor=false");
        HttpClient client = new DefaultHttpClient();
        HttpResponse response;
        stringBuilder = new StringBuilder();


            response = client.execute(httppost);
            HttpEntity entity = response.getEntity();
            InputStream stream = entity.getContent();
            int b;
            while ((b = stream.read()) != -1) {
                stringBuilder.append((char) b);
            }
        } catch (ClientProtocolException e) {
        } catch (IOException e) {
        }

        JSONObject jsonObject = new JSONObject();
        try {
            jsonObject = new JSONObject(stringBuilder.toString());
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        return jsonObject;
    }

now pass that JSONObject to getLatLong() method like following

现在将JSONObject传递给getLatLong()方法,如下所示

public static boolean getLatLong(JSONObject jsonObject) {

        try {

            longitute = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
                .getJSONObject("geometry").getJSONObject("location")
                .getDouble("lng");

            latitude = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
                .getJSONObject("geometry").getJSONObject("location")
                .getDouble("lat");

        } catch (JSONException e) {
            return false;

        }

        return true;
    }

I hope this helps to you nd others..!! Thank you..!!

我希望这对你和其他人有帮助.. !!谢谢..!!

#4


6  

The following code will work for google apiv2:

以下代码适用于google apiv2:

public void convertAddress() {
    if (address != null && !address.isEmpty()) {
        try {
            List<Address> addressList = geoCoder.getFromLocationName(address, 1);
            if (addressList != null && addressList.size() > 0) {
                double lat = addressList.get(0).getLatitude();
                double lng = addressList.get(0).getLongitude();
            }
        } catch (Exception e) {
            e.printStackTrace();
        } // end catch
    } // end if
} // end convertAddress

Where address is the String (123 Testing Rd City State zip) you want to convert to LatLng.

其中address是要转换为LatLng的String(123 Testing Rd City State zip)。

#5


3  

This is how you can find the latitude and longitude of where we have click on map.

这是您可以找到我们点击地图的纬度和经度的方法。

public boolean onTouchEvent(MotionEvent event, MapView mapView) 
{   
    //---when user lifts his finger---
    if (event.getAction() == 1) 
    {                
        GeoPoint p = mapView.getProjection().fromPixels(
            (int) event.getX(),
            (int) event.getY());

        Toast.makeText(getBaseContext(), 
             p.getLatitudeE6() / 1E6 + "," + 
             p.getLongitudeE6() /1E6 , 
             Toast.LENGTH_SHORT).show();
    }                            
    return false;
} 

it works well.

它运作良好。

To get the location's address we can use geocoder class.

要获取位置的地址,我们可以使用地理编码器类。

#6


1  

An answer to Kandha problem above :

以上Kandha问题的答案:

It throws the "java.io.IOException service not available" i already gave those permission and include the library...i can get map view...it throws that IOException at geocoder...

它抛出“java.io.IOException服务不可用”我已经给了这些权限并包含了库...我可以获得地图视图...它会在地理编码器处抛出IOException ...

I just added a catch IOException after the try and it solved the problem

我在尝试后添加了一个catch IOException,它解决了问题

    catch(IOException ioEx){
        return null;
    }

#7


0  

Geocoder coder = new Geocoder(this);
        List<Address> addresses;
        try {
            addresses = coder.getFromLocationName(address, 5);
            if (addresses == null) {
            }
            Address location = addresses.get(0);
            double lat = location.getLatitude();
            double lng = location.getLongitude();
            Log.i("Lat",""+lat);
            Log.i("Lng",""+lng);
            LatLng latLng = new LatLng(lat,lng);
            MarkerOptions markerOptions = new MarkerOptions();
            markerOptions.position(latLng);
            googleMap.addMarker(markerOptions);
            googleMap.animateCamera(CameraUpdateFactory.newLatLngZoom(latLng,12));
        } catch (IOException e) {
            e.printStackTrace();
        }

#1


119  

public GeoPoint getLocationFromAddress(String strAddress){

Geocoder coder = new Geocoder(this);
List<Address> address;
GeoPoint p1 = null;

try {
    address = coder.getFromLocationName(strAddress,5);
    if (address==null) {
       return null;
    }
    Address location=address.get(0);
    location.getLatitude();
    location.getLongitude();

    p1 = new GeoPoint((double) (location.getLatitude() * 1E6),
                      (double) (location.getLongitude() * 1E6));

    return p1;
    }
}

strAddress is a string containing the address. The address variable holds the converted addresses.

strAddress是包含地址的字符串。地址变量保存转换后的地址。

#2


58  

Ud_an's solution with updated API's

Ud_an的解决方案包含更新的API

Note: LatLng class is part of Google Play Services.

注意:LatLng类是Google Play服务的一部分。

Mandatory:

强制性:

<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>

<uses-permission android:name="android.permission.INTERNET"/>

Update: If you have target SDK 23 and above, make sure you take care of runtime permission for location.

更新:如果您有目标SDK 23及更高版本,请确保您负责位置的运行时权限。

public LatLng getLocationFromAddress(Context context,String strAddress) {

    Geocoder coder = new Geocoder(context);
    List<Address> address;
    LatLng p1 = null;

    try {
        // May throw an IOException
        address = coder.getFromLocationName(strAddress, 5);
        if (address == null) {
            return null;
        }

        Address location = address.get(0);
        p1 = new LatLng(location.getLatitude(), location.getLongitude() );

    } catch (IOException ex) {

        ex.printStackTrace();
    }

    return p1;
}

#3


51  

If you want to place your address in google map then easy way to use following

如果您想将地址放在谷歌地图中,​​那么可以轻松使用以下内容

Intent searchAddress = new  Intent(Intent.ACTION_VIEW,Uri.parse("geo:0,0?q="+address));
startActivity(searchAddress);

OR

要么

if you needed to get lat long from your address then use Google Place Api following

如果您需要从您的地址获得很长的时间,请使用Google Place Api

create a method that returns a JSONObject with the response of the HTTP Call like following

创建一个方法,返回带有HTTP调用响应的JSONObject,如下所示

public static JSONObject getLocationInfo(String address) {
        StringBuilder stringBuilder = new StringBuilder();
        try {

        address = address.replaceAll(" ","%20");    

        HttpPost httppost = new HttpPost("http://maps.google.com/maps/api/geocode/json?address=" + address + "&sensor=false");
        HttpClient client = new DefaultHttpClient();
        HttpResponse response;
        stringBuilder = new StringBuilder();


            response = client.execute(httppost);
            HttpEntity entity = response.getEntity();
            InputStream stream = entity.getContent();
            int b;
            while ((b = stream.read()) != -1) {
                stringBuilder.append((char) b);
            }
        } catch (ClientProtocolException e) {
        } catch (IOException e) {
        }

        JSONObject jsonObject = new JSONObject();
        try {
            jsonObject = new JSONObject(stringBuilder.toString());
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        return jsonObject;
    }

now pass that JSONObject to getLatLong() method like following

现在将JSONObject传递给getLatLong()方法,如下所示

public static boolean getLatLong(JSONObject jsonObject) {

        try {

            longitute = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
                .getJSONObject("geometry").getJSONObject("location")
                .getDouble("lng");

            latitude = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
                .getJSONObject("geometry").getJSONObject("location")
                .getDouble("lat");

        } catch (JSONException e) {
            return false;

        }

        return true;
    }

I hope this helps to you nd others..!! Thank you..!!

我希望这对你和其他人有帮助.. !!谢谢..!!

#4


6  

The following code will work for google apiv2:

以下代码适用于google apiv2:

public void convertAddress() {
    if (address != null && !address.isEmpty()) {
        try {
            List<Address> addressList = geoCoder.getFromLocationName(address, 1);
            if (addressList != null && addressList.size() > 0) {
                double lat = addressList.get(0).getLatitude();
                double lng = addressList.get(0).getLongitude();
            }
        } catch (Exception e) {
            e.printStackTrace();
        } // end catch
    } // end if
} // end convertAddress

Where address is the String (123 Testing Rd City State zip) you want to convert to LatLng.

其中address是要转换为LatLng的String(123 Testing Rd City State zip)。

#5


3  

This is how you can find the latitude and longitude of where we have click on map.

这是您可以找到我们点击地图的纬度和经度的方法。

public boolean onTouchEvent(MotionEvent event, MapView mapView) 
{   
    //---when user lifts his finger---
    if (event.getAction() == 1) 
    {                
        GeoPoint p = mapView.getProjection().fromPixels(
            (int) event.getX(),
            (int) event.getY());

        Toast.makeText(getBaseContext(), 
             p.getLatitudeE6() / 1E6 + "," + 
             p.getLongitudeE6() /1E6 , 
             Toast.LENGTH_SHORT).show();
    }                            
    return false;
} 

it works well.

它运作良好。

To get the location's address we can use geocoder class.

要获取位置的地址,我们可以使用地理编码器类。

#6


1  

An answer to Kandha problem above :

以上Kandha问题的答案:

It throws the "java.io.IOException service not available" i already gave those permission and include the library...i can get map view...it throws that IOException at geocoder...

它抛出“java.io.IOException服务不可用”我已经给了这些权限并包含了库...我可以获得地图视图...它会在地理编码器处抛出IOException ...

I just added a catch IOException after the try and it solved the problem

我在尝试后添加了一个catch IOException,它解决了问题

    catch(IOException ioEx){
        return null;
    }

#7


0  

Geocoder coder = new Geocoder(this);
        List<Address> addresses;
        try {
            addresses = coder.getFromLocationName(address, 5);
            if (addresses == null) {
            }
            Address location = addresses.get(0);
            double lat = location.getLatitude();
            double lng = location.getLongitude();
            Log.i("Lat",""+lat);
            Log.i("Lng",""+lng);
            LatLng latLng = new LatLng(lat,lng);
            MarkerOptions markerOptions = new MarkerOptions();
            markerOptions.position(latLng);
            googleMap.addMarker(markerOptions);
            googleMap.animateCamera(CameraUpdateFactory.newLatLngZoom(latLng,12));
        } catch (IOException e) {
            e.printStackTrace();
        }