Java正则表达式用逗号分割字符串但忽略引号和括号[复制]

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Java: splitting a comma-separated string but ignoring commas in quotes 9 answers

Java:拆分以逗号分隔的字符串,但忽略引号9答案中的逗号

I'm stuck with this regex.

我坚持这个正则表达式。

So, I have input as:

所以,我输入:

"Crane device, (physical object)"(X1,x2,x4), not "Seen by research nurse (finding)", EntirePatellaBodyStructure(X1,X8), "Besnoitia wallacei (organism)", "Catatropis (organism)"(X1,x2,x4), not IntracerebralRouteQualifierValue, "Diospyros virginiana (organism)"(X1,x2,x4), not SuturingOfHandProcedure(X1)

“起重机装置,(物理对象)”(X1,x2,x4),不是“由研究护士(发现)看见”,EntirePatellaBodyStructure(X1,X8),“Besnoitia wallacei(有机体)”,“Catatropis(有机体)”( X1,x2,x4),而不是IntracerebralRouteQualifierValue,“Diospyros virginiana(有机体)”(X1,x2,x4),而不是SuturingOfHandProcedure(X1)

and in the end I would like to get is:

最后我想得到的是:

"Crane device, (physical object)"(X1,x2,x4)

“起重机装置,(物理对象)”(X1,x2,x4)

not "Seen by research nurse (finding)"

不是“由研究护士(发现)看到”

EntirePatellaBodyStructure(X1,X8)
"Besnoitia wallacei (organism)"

“Besnoitia wallacei(有机体)”

"Catatropis (organism)"(X1,x2,x4)
not IntracerebralRouteQualifierValue
"Diospyros virginiana (organism)"(X1,x2,x4)

“Diospyros virginiana(有机体)”(X1,x2,x4)

not SuturingOfHandProcedure(X1)

I've tried regex

我试过正则表达式

(\'[^\']*\')|(\"[^\"]*\")|([^,]+)|\\s*,\\s*

It works if I don't have a comma inside parentheses.

如果我在括号内没有逗号,它可以工作。

4 个解决方案

#1

RegEx

(\w+\s)?("[^"]+"|\w+)(\(\w\d(,\w\d)*\))?

Java Code

String input = ... ;
Matcher m = Pattern.compile(
          "(\\w+\\s)?(\"[^\"]+\"|\\w+)(\\(\\w\\d(,\\w\\d)*\\))?").matcher(input);
while(matcher.find()) {
    System.out.println(matcher.group());
}

Output

"Crane device, (physical object)"(X1,x2,x4)
not "Seen by research nurse (finding)"
EntirePatellaBodyStructure(X1,X8)
not "Besnoitia wallacei (organism)"(X1,x2,x4)
not "Catatropis (organism)"(X1,x2,x4)
not IntracerebralRouteQualifierValue
not "Diospyros virginiana (organism)"(X1,x2,x4)
not SuturingOfHandProcedure(X1)

#2

Don't use regexes for this. Write a simple parser that keeps track of the number of parentheses encountered, and whether or not you are inside quotes. For more information, see: RegEx match open tags except XHTML self-contained tags

不要使用正则表达式。编写一个简单的解析器,跟踪遇到的括号数,以及是否在引号内。有关更多信息,请参阅:RegEx匹配除XHTML自包含标记之外的开放标记

#3

Would this do what you need?

这会做你需要的吗?

System.out.println(yourString.replaceAll(", not", "\nnot"));

#4

Assuming that there is no possibility of nesting () within (), and no possibility of (say) \" within "", you can write something like:

假设在()中没有嵌套()的可能性,并且没有(比如说)“在”内“的可能性,你可以这样写:

private static final Pattern CUSTOM_SPLIT_PATTERN =
    Pattern.compile("\\s*((?:\"[^\"]*\"|[(][^)]*[)]|[^\"(]+)+)");
private static final String[] customSplit(final String input) {
    final List<String> ret = new ArrayList<String>();
    final Matcher m = CUSTOM_SPLIT_PATTERN.matcher(input);
    while(m.find()) {
        ret.add(m.group(1));
    }
    return ret.toArray(new String[ret.size()]);
}

(disclaimer: not tested).

(免责声明:未经测试)。

#1