银行金额格式转换以及数字金额转换成汉子金额并保留两位小数

package com.cdrcb.fifp.utils;

import java.math.BigDecimal;
import java.util.Map;

/**2015-6-17 k.sea*/
public class NumberToCN {

   
     // 汉语中数字大写
 private static final String[] CN_UPPER_NUMBER = { "零", "壹", "贰", "叁", "肆","伍", "陆", "柒", "捌", "玖" };
    // 汉语中货币单位大写，这样的设计类似于占位符
    private static final String[] CN_UPPER_MONETRAY_UNIT = { "分", "角", "元","拾", "佰", "仟", "万", "拾", "佰", "仟", "亿", "拾", "佰", "仟", "兆", "拾","佰", "仟" };
    // 特殊字符：整
    private static final String CN_FULL = "整";
     // 特殊字符：负
    private static final String CN_NEGATIVE = "负";
    // 金额的精度，默认值为2
    private static final int MONEY_PRECISION = 2;
     // 特殊字符：零元整
    private static final String CN_ZEOR_FULL = "零元" + CN_FULL;

    /**
     * 把输入的金额转换为汉语中人民币的大写
     *
     * @param numberOfMoney
     *         输入的金额
     * @return 对应的汉语大写
     */
    public static String numberFondsConvertToBigChars(BigDecimal numberOfMoney) {
        StringBuffer sb = new StringBuffer();
        // -1, 0, or 1 as the value of this BigDecimal is negative, zero, or
        // positive.
        int signum = numberOfMoney.signum();
        // 零元整的情况
        if (signum == 0) {
            return CN_ZEOR_FULL;
        }
        //这里会进行金额的四舍五入
        long number = numberOfMoney.movePointRight(MONEY_PRECISION).setScale(0, 4).abs().longValue();
        // 得到小数点后两位值
        long scale = number % 100;
        int numUnit = 0;
        int numIndex = 0;
        boolean getZero = false;
        // 判断最后两位数，一共有四中情况：00 = 0, 01 = 1, 10, 11
        if (!(scale > 0)) {
            numIndex = 2;
            number = number / 100;
            getZero = true;
        }
        if ((scale > 0) && (!(scale % 10 > 0))) {
            numIndex = 1;
            number = number / 10;
            getZero = true;
        }
        int zeroSize = 0;
        while (true) {
            if (number <= 0) {
                break;
            }
            // 每次获取到最后一个数
            numUnit = (int) (number % 10);
            if (numUnit > 0) {
                if ((numIndex == 9) && (zeroSize >= 3)) {
                    sb.insert(0, CN_UPPER_MONETRAY_UNIT[6]);
                }
                if ((numIndex == 13) && (zeroSize >= 3)) {
                    sb.insert(0, CN_UPPER_MONETRAY_UNIT[10]);
                }
                sb.insert(0, CN_UPPER_MONETRAY_UNIT[numIndex]);
                sb.insert(0, CN_UPPER_NUMBER[numUnit]);
                getZero = false;
                zeroSize = 0;
            } else {
                ++zeroSize;
                if (!(getZero)) {
                    sb.insert(0, CN_UPPER_NUMBER[numUnit]);
                }
                if (numIndex == 2) {
                    if (number > 0) {
                        sb.insert(0, CN_UPPER_MONETRAY_UNIT[numIndex]);
                    }
                } else if (((numIndex - 2) % 4 == 0) && (number % 1000 > 0)) {
                    sb.insert(0, CN_UPPER_MONETRAY_UNIT[numIndex]);
                }
                getZero = true;
            }
            // 让number每次都去掉最后一个数
            number = number / 10;
            ++numIndex;
        }
        // 如果signum == -1，则说明输入的数字为负数，就在最前面追加特殊字符：负
        if (signum == -1) {
            sb.insert(0, CN_NEGATIVE);
        }
        // 输入的数字小数点后两位为"00"的情况，则要在最后追加特殊字符：整
        if (!(scale > 0)) {
            sb.append(CN_FULL);
        }
        return sb.toString();
    }
   
 // 分割金额 如：1234567.86 分割成1,234,567.86
 public static String fondsFormat(String number) {
  
  // 获取小数点前的整数与小数点后面的整数
  String firstNumber = number.substring(0, number.indexOf("."));
  String lastNumber = number.substring(number.indexOf(".")+1);
  StringBuilder sb = new StringBuilder(firstNumber);
  //将其数字反转
  firstNumber = sb.reverse().toString();
  //存取反正后分割数据
  StringBuilder numberSB=new StringBuilder();
  int leng=firstNumber.length();
  leng= (leng % 3==0?leng/3:(leng/3)+1);
  for (int i = 0; i <leng ; i++) {
   numberSB.append(",");
   if(i+1<leng)
   numberSB.append(firstNumber.substring(i*3, (i+1)*3));
   if(i+1==leng)
    numberSB.append(firstNumber.substring(i*3)); 
  }
  String resultNumber=numberSB.reverse().toString();
  resultNumber=resultNumber.substring(0, resultNumber.length()-1);
  resultNumber+="."+lastNumber;
  return resultNumber;
 }
}