C语言——实例065 一个最优美的图案。

062 到 065 可不理

/*
	Name: 
	Copyright: 
	Author: 
	Date: 31/07/17 14:37
	Description: 
		【程序65】题目：一个最优美的图案。　　　
	?
*/

#include "graphics.h"
#include "math.h"
#include "dos.h"
#include "conio.h"
#include "stdlib.h"
#include "stdio.h"
#include "stdarg.h"
#define MAXPTS 15
#define PI 3.1415926
struct PTS 
{
	int x,y;
};

double AspectRatio = 0.85;

void LineToDemo(void)
{
	struct viewporttype vp;
	struct PTS points[MAXPTS];
	int i, j, h, w, xcenter, ycenter;
	int radius, angle, step;
	double rads;
	printf(" MoveTo / LineTo Demonstration" );
	getviewsettings( &vp );
	h = vp.bottom - vp.top;
	w = vp.right - vp.left;
	xcenter = w / 2; /* Determine the center of circle */ 
	ycenter = h / 2;
	radius = (h - 30) / (AspectRatio * 2);
	step = 360 / MAXPTS; /* Determine # of increments */ 
	angle = 0; /* Begin at zero degrees */ 
	for(i = 0 ;i < MAXPTS ;++i )
	{ /* Determine circle intercepts */ 
		rads = (double)angle * PI / 180.0; /* Convert angle to radians */ 
		points[i].x = xcenter + (int)( cos(rads) * radius );
		points[i].y = ycenter - (int)( sin(rads) * radius * AspectRatio );
		angle += step; /* Move to next increment */ 
	}
	circle( xcenter, ycenter, radius ); /* Draw bounding circle */ 
	for( i=0 ; i<MAXPTS ; ++i )
	{ /* Draw the cords to the circle */ 
		for( j=i ; j<MAXPTS ; ++j )
		{ /* For each remaining intersect */ 
			moveto(points[i].x, points[i].y); /* Move to beginning of cord */ 
			lineto(points[j].x, points[j].y); /* Draw the cord */ 
		} 
	} 
}

int main()
{
	int driver,mode;
	driver = CGA;
	mode = CGAC0;
	initgraph(&driver,&mode,"");
	setcolor(3);
	setbkcolor(GREEN);
	LineToDemo();
	return 0;
}