C ++保存在函数中创建的对象的指针

I have struct called Rectangle:

我有一个名为Rectangle的结构:

 struct Rectangle {
    std::vector<float> m_min;
    std::vector<float> m_max;
    exType timeOfArrival, timeOfexpiry;
    unsigned int id;
};

In a function I pass a rectangle by value and save the object into a DB. I want to return the pointer of the rectangle so that I can use it out of the function and save it (the pointer) in a vector. From what I have read as of C++11 there is no need to return a pointer so I return the rectangle. Is this the right way? How can I have the pointer to the object created in the function?

在函数中,我按值传递一个矩形并将对象保存到DB中。我想返回矩形的指针,以便我可以将其用于函数并将其(指针)保存在向量中。从我从C ++ 11开始读到的,没有必要返回一个指针,所以我返回矩形。这是正确的方法吗?如何获得指向函数中创建的对象的指针?

This is how I do it now:

这就是我现在的做法:

Rectangle Insert(Rectangle rect){// "Insert" is a function of another class
    SaveIntoToDB(rect);// Calls other functions that use reference
    return rect;
}

I need something fast that does not create duplicates in memory.

我需要快速的东西,不会在内存中创建重复。

1 个解决方案

#1

What would be wrong with this?

这会有什么问题?

void Insert(const Rectangle &rect)
{
 ...
}

Called like

Rect myrect = something...;
Insert(myrect);
doSomething(&myrect);  // Do something with pointer to myrect

Generally, based on your question and code, you should be avoiding pointers completely at this stage.

通常,根据您的问题和代码,您应该在此阶段完全避免使用指针。

#1