Java中计算时间差的方法

时间:2021-07-23 03:59:29

本文实例讲述了Java中计算时间差的方法。分享给大家供大家参考。具体如下:

假设现在是2004-03-26 13:31:40
过去是:2004-01-02 11:30:24
要获得两个日期差,差的形式为:XX天XX小时XX分XX秒

方法一:

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DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try
{
  Date d1 = df.parse("2004-03-26 13:31:40");
  Date d2 = df.parse("2004-01-02 11:30:24");
  long diff = d1.getTime() - d2.getTime();
  long days = diff / (1000 * 60 * 60 * 24);
}
catch (Exception e)
{
}

方法二:

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SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date now = df.parse("2004-03-26 13:31:40");
java.util.Date date=df.parse("2004-01-02 11:30:24");
long l=now.getTime()-date.getTime();
long day=l/(24*60*60*1000);
long hour=(l/(60*60*1000)-day*24);
long min=((l/(60*1000))-day*24*60-hour*60);
long s=(l/1000-day*24*60*60-hour*60*60-min*60);
System.out.println(""+day+"天"+hour+"小时"+min+"分"+s+"秒");

方法三:

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SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date begin=dfs.parse("2004-01-02 11:30:24");
java.util.Date end = dfs.parse("2004-03-26 13:31:40");
long between=(end.getTime()-begin.getTime())/1000;
//除以1000是为了转换成秒
long day1=between/(24*3600);
long hour1=between%(24*3600)/3600;
long minute1=between%3600/60;
long second1=between%60/60;
System.out.println(""+day1+"天"+hour1+"小时"+minute1+"分"+second1+"秒");

希望本文所述对大家的java程序设计有所帮助。