要为LIKE运算符通配符搜索转义的T-SQL特殊字符

SQL Server has the LIKE operator to handle wildcard searches. My customer wants to use the "*" (asterisk) character in the user interface of an application as the wildcard character. I'm just wondering if there are any standard characters that I need to worry about (that are used as special characters in SQL Server) besides the "%" (percent) character itself before performing a LIKE wilcard search in case their keyword contains a "%" and needs to find a "%" in the actual string. If so, what are they?

SQL Server具有LIKE运算符来处理通配符搜索。我的客户希望在应用程序的用户界面中使用“*”（星号）字符作为通配符。我只是想知道是否有任何标准字符我需要担心（在SQL Server中用作特殊字符）除了“％”（百分比）字符本身之前执行LIKE威尔卡搜索以防其关键字包含“％”并且需要在实际字符串中找到“％”。如果是这样，他们是什么？

So please assume that [table1].[column1] will never have a "*" (asterisk) in the text string!

所以请假设[table1]。[column1]在文本字符串中永远不会有“*”（星号）！

Here's what I have so far. Do I need to handle more situations other than the standard "%" character and the custom "*"

这是我到目前为止所拥有的。我是否需要处理除标准“％”字符和自定义“*”之外的更多情况

-- custom replacement
select REPLACE('xxx*xxx', '*', '%')

-- standard replacements
select REPLACE('xxx%xxx', '%', '[%]')
select REPLACE('xxx_xxx', '_', '[_]')  -- ???
select REPLACE('xxx[xxx', '[', '[[]')  -- ???
select REPLACE('xxx]xxx', ']', '[]]')  -- ???

Example:

例：

SET @p = REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(@p, ']', '[]]'), '[', '[[]'), '_', '[_]'), '%', '[%]'), '*', '%')

SELECT 'xxxxxxxxx%xxxxxx' LIKE @p

SELECT [table1].[column1] LIKE @p

2 个解决方案

#1

It looks like you got them all, although I think escaping ']' is unnecessary. Technically you should just need to escape the opening bracket ('[').

看起来你得到了所有这些，虽然我认为逃避']'是不必要的。从技术上讲，你应该只需要逃离开口括号（'['）。

DECLARE @Table1 TABLE
(
   Column1 VARCHAR(32) NOT NULL PRIMARY KEY
);

INSERT @Table1(Column1)
VALUES
   ('abc%def'),
   ('abc_def'),
   ('abc[d]ef'),
   ('abc def'),
   ('abcdef');

DECLARE @p VARCHAR(32) = 'abc*]*';

DECLARE @Escaped VARCHAR(64) = REPLACE(@p, '[', '[[]');
SET @Escaped = REPLACE(@Escaped, '_', '[_]');
SET @Escaped = REPLACE(@Escaped, '%', '[%]');
SET @Escaped = REPLACE(@Escaped, '*', '%');

SELECT T.Column1
FROM @Table1 T
WHERE T.Column1 LIKE @Escaped;

#2

Looks good!! - Have a look here for all the information related to the LIKE clause.

看起来不错！！ - 看看这里有关LIKE子句的所有信息。

Also List of special characters for SQL LIKE clause

还有SQL LIKE子句的特殊字符列表

#1