如何通过名称从res / raw读取文件

I want to open a file from the folder res/raw/. I am absolutely sure that the file exists. To open the file I have tried

我想从res / raw /文件夹中打开一个文件。我绝对相信文件存在。要打开我试过的文件

File ddd = new File("res/raw/example.png");

The command

命令

ddd.exists();

yields FALSE. So this method does not work.

收益率为假。所以这种方法不起作用。

Trying

试

MyContext.getAssets().open("example.png");

ends up in an exception with getMessage() "null".

以getMessage（）“null”结束异常。

Simply using

简单地使用

R.raw.example

is not possible because the filename is only known during runtime as a string.

因为文件名仅在运行时作为字符串被识别，所以是不可能的。

Why is it so difficult to access a file in the folder /res/raw/ ?

为什么访问文件夹/ res / raw /中的文件如此困难？

3 个解决方案

#1

100

With the help of the given links I was able to solve the problem myself. The correct way is to get the resource ID with

在给定链接的帮助下，我能够自己解决问题。正确的方法是获取资源ID

getResources().getIdentifier("FILENAME_WITHOUT_EXTENSION",
                             "raw", getPackageName());

To get it as a InputStream

将其作为InputStream

InputStream ins = getResources().openRawResource(
            getResources().getIdentifier("FILENAME_WITHOUT_EXTENSION",
            "raw", getPackageName()));

#2

Here is example of taking XML file from raw folder:

以下是从raw文件夹中获取XML文件的示例：

 InputStream XmlFileInputStream = getResources().openRawResource(R.raw.taskslists5items); // getting XML

Then you can:

然后你可以：

 String sxml = readTextFile(XmlFileInputStream);

when:

什么时候：

 public String readTextFile(InputStream inputStream) {
        ByteArrayOutputStream outputStream = new ByteArrayOutputStream();

        byte buf[] = new byte[1024];
        int len;
        try {
            while ((len = inputStream.read(buf)) != -1) {
                outputStream.write(buf, 0, len);
            }
            outputStream.close();
            inputStream.close();
        } catch (IOException e) {

        }
        return outputStream.toString();
    }

#3

You can read files in raw/res using getResources().openRawResource(R.raw.myfilename).

您可以使用getResources（）。openRawResource（R.raw.myfilename）读取raw / res中的文件。

BUT there is an IDE limitation that the file name you use can only contain lower case alphanumeric characters and dot. So file names like XYZ.txt or my_data.bin will not be listed in R.

但是有一个IDE限制，您使用的文件名只能包含小写字母数字字符和点。因此，文件名如XYZ.txt或my_data.bin将不会列在R中。

#1

100