
C# -- 等待异步操作执行完成的方式
1. 等待异步操作的完成,代码实现:
class Program
{
static void Main(string[] args)
{
Func<int, int> mySum1 = SumNumbers;
Func<int, int> mySum2 = SumNumbers;
Func<int, int> mySum3 = SumNumbers; AsyncCallback callback = c => Console.WriteLine("线程ID:{0},回调函数执行:{1}",Thread.CurrentThread.ManagedThreadId,c.AsyncState); IAsyncResult result1= mySum1.BeginInvoke(, callback, "第一个异步");
IAsyncResult result2= mySum2.BeginInvoke(, callback, "第二个异步");
IAsyncResult result3= mySum3.BeginInvoke(, callback, "第三个异步"); //异步等待方式1:使用EndInvoke
int asyc1 = mySum1.EndInvoke(result1);
Console.WriteLine("第一个异步已经执行完成,结果:{0}",asyc1); //异步等待方式2:使用AsyncWaitHandle.WaitOne,参数-1表示一直等待到执行完成
if (result2.AsyncWaitHandle.WaitOne(-))
{
Console.WriteLine("第二个异步执行完成");
} //异步等待方式3:使用IsCompleted判断
while (!result3.IsCompleted)
{
Console.WriteLine("第三个异步还在执行中....");
Thread.Sleep();
}
Console.WriteLine("第三个异步执行完成"); Console.ReadKey();
} public static int SumNumbers(int count)
{
int sum = ;
for (int i = ; i < count; i++)
{
sum += i;
} Thread.Sleep();
return sum;
}
}
2. 代码执行结果: