C++位操作符总结

时间:2023-03-09 08:25:11
C++位操作符总结

C++位操作符总结

 #include <stdio.h>
#include <memory.h>
#include <malloc.h>
#define MaxBinLength 16 //获取无符号数的二进制,这是我自己写的,更简单的方法可以用bitset代替
char* getUnsignedBinary(unsigned int num)
{
int len = MaxBinLength -;
char *bin = (char*)malloc((MaxBinLength + )*sizeof(char));
memset(bin,'',MaxBinLength);
bin[MaxBinLength] = ;
while(num/ != ){
bin[len--] = '' + num%;
num/=;
}
if(num!=)
bin[len--] = '';
return bin;
} void flip(unsigned short num)
{
printf("位求反,运算符为 ~ ,功能简单,将操作数的每一个二进制位取反\n");
printf("原值:%6d %s\n",num,getUnsignedBinary(num));
printf("新值:%6d %s\n",~num,getUnsignedBinary(~num));
printf("-------------------------\n");
} void left_shift(unsigned short num,unsigned short offset)
{
printf("左移运算,运算符为 << ,将操作数的二进制位向左移动指定的offset(%d)位数,offset必须小于原数的位数,右边新加的位以0填充\n",offset);
printf("原值:%6d %s\n",num,getUnsignedBinary(num));
printf("新值:%6d %s\n",num<<offset,getUnsignedBinary(num<<offset));
printf("-------------------------\n");
} void right_shift(unsigned short num,unsigned short offset)
{
printf("右移运算,运算符为 >> ,将操作数的二进制位向右移动指定的offset(%d)位数,offset必须小于原数的位数,\n\
如果操作数无符号,左边新加的位以0填充,如果操作数有符号,右边新加的位可能以符号位填充,也可能以0填充,\n\
具体依赖于机器,见注释\n",offset);
printf("原值:%6d %s\n",num,getUnsignedBinary(num));
printf("新值:%6d %s\n",num>>offset,getUnsignedBinary(num>>offset));
printf("-------------------------\n");
} void weiyu(unsigned short num,unsigned short num_1)
{
printf("位与,运算符为 & ,对两个操作数的每一个对应二进制位进行'与'运算,运算方式类似于&&运算\n");
printf("原值:%6d %s\n",num,getUnsignedBinary(num));
printf("原值:%6d %s\n",num_1,getUnsignedBinary(num_1));
printf("新值:%6d %s\n",num&num_1,getUnsignedBinary(num&num_1));
printf("-------------------------\n");
} void weihuo(unsigned short num,unsigned short num_1)
{
printf("位或,运算符为 | ,对两个操作数的每一个对应二进制位进行'或'运算,运算方式类似于||运算\n");
printf("原值:%6d %s\n",num,getUnsignedBinary(num));
printf("原值:%6d %s\n",num_1,getUnsignedBinary(num_1));
printf("新值:%6d %s\n",num|num_1,getUnsignedBinary(num|num_1));
printf("-------------------------\n");
} void weiyihuo(unsigned short num,unsigned short num_1)
{
printf("位异或,运算符为 ^ ,对两个操作数的每一个对应二进制位进行'异或'运算,两个位不同则为1,相同则为0\n");
printf("原值:%6d %s\n",num,getUnsignedBinary(num));
printf("原值:%6d %s\n",num_1,getUnsignedBinary(num_1));
printf("新值:%6d %s\n",num^num_1,getUnsignedBinary(num^num_1));
printf("-------------------------\n");
} void zhushi()
{
printf("注释:位操作符只能操作整数,这个整数可以是有符号的也可以是无符号的,\n\
如果操作数为负数,则位如何处理其符号位依赖于机器,所以在一个环境中实现的\n\
程序可能无法用于另一环境,因此强烈建议使用unsigned整数作为操作数\n\
参考<<C++primer>>(人民邮电出版社第4版)155页\n");
printf("-------------------------\n");
} int main()
{
unsigned short num = ,num_1 = ,offset = ;
flip(num);
left_shift(num,offset);
right_shift(num,offset);
weiyu(num,num_1);
weihuo(num,num_1);
weiyihuo(num,num_1);
zhushi();
return ;
}

后来又自己试了一下,当在左移运算中,offset是可以大于操作数的长度的。当offset大一操作数长度的时候,操作的结果会自动更改整数类型,以容纳更多的位数,例如unsigned char可以变为short,short可以变为int等。

而右移运算中,无论offset为何值,操作结果的长度不会发证变化。

看demo,只是经过简单的验证。

C++位操作符总结

 #include <bitset>
#include <iostream>
#include <iomanip>
using namespace std; #define uint8_t unsigned char
#define uint16_t unsigned short
#define uint32_t unsigned int bitset<> getBinary32(int num)
{
bitset<> bit(num);
return bit;
} bitset<> getBinary8(uint8_t num)
{
bitset<> bit(num);
return bit;
} int main()
{
uint8_t a = ;
//左移
cout<<"左移"<<endl<<"a="<<(int)a<<" "<<getBinary8(a)<<endl;
for(int i = ;i<=;i++)
{
if(i < )
{
uint16_t b = a<<i;
cout<<"b="<<setw()<<(unsigned short)b<<" "<<getBinary32(b)<<endl;
}
else
{
uint32_t b = a<<i;
cout<<"b="<<setw()<<(unsigned int)b<<" "<<getBinary32(b)<<endl;
}
} //右移
cout<<"右移"<<endl<<"a="<<(int)a<<" "<<getBinary8(a)<<endl;
for(i = ;i<=;i++)
{
if(i < )
{
uint16_t b = a>>i;
cout<<"b="<<setw()<<(unsigned short)b<<" "<<getBinary32(b)<<endl;
}
else
{
uint32_t b = a>>i;
cout<<"b="<<setw()<<(unsigned int)b<<" "<<getBinary32(b)<<endl;
}
}
return ;
}