![[LintCode] Happy Number 快乐数 [LintCode] Happy Number 快乐数](https://image.shishitao.com:8440/aHR0cHM6Ly9ia3FzaW1nLmlrYWZhbi5jb20vdXBsb2FkL2NoYXRncHQtcy5wbmc%2FIQ%3D%3D.png?!?w=700&webp=1)
Write an algorithm to determine if a number is happy.
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example
19 is a happy number
1^2 + 9^2 = 82
8^2 + 2^2 = 68
6^2 + 8^2 = 100
1^2 + 0^2 + 0^2 = 1
LeetCode上的原题,请参见我之前的博客Happy Number。
解法一:
class Solution {
public:
/**
* @param n an integer
* @return true if this is a happy number or false
*/
bool isHappy(int n) {
set<int> s;
while (n != ) {
int t = ;
while (n) {
t += (n % ) * (n % );
n /= ;
}
n = t;
if (s.count(n)) break;
else s.insert(n);
}
return n == ;
}
};
解法二:
class Solution {
public:
/**
* @param n an integer
* @return true if this is a happy number or false
*/
bool isHappy(int n) {
while (n != && n != ) {
int t = ;
while (n) {
t += (n % ) * (n % );
n /= ;
}
n = t;
}
return n == ;
}
};