lc面试准备:Implement Queue using Stacks

时间:2023-03-09 17:16:54
lc面试准备:Implement Queue using Stacks

1 题目

Implement the following operations of a queue using stacks.

  • push(x) -- Push element x to the back of queue.
  • pop() -- Removes the element from in front of queue.
  • peek() -- Get the front element.
  • empty() -- Return whether the queue is empty.

    Notes:
  • You must use only standard operations of a stack -- which means only push to top, peek/pop from top, size, and is empty operations are valid.
  • Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
  • You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).

接口: 实现4个方法

2 思路

用2个stack,inboxoutbox

Queue:

  • Push the new element onto inbox

Dequeue:

  • If outbox is empty, refill it by popping each element from inbox and pushing it onto outbox
  • Pop and return the top element from outbox

each element will be in each stack exactly once - meaning each element will be pushed twice and popped twice, giving amortized constant time operations.(用这个方法,每个元素只在两个stack中存储一份,每个元素将会被push pop两次,MyQueue的pop操作的时间复杂度是分摊的时间常数,最好O(1),最坏O(n)).

复杂度:push O(1); pop O(1) or O(n); peek O(1) or O(n); empty O(1)

3 代码

MyQueue.java

import java.util.LinkedList;

// Java编程思想推荐在使用stack的时候,用LinkedList替代。
class MyQueue {
LinkedList<Integer> inbox = new LinkedList<Integer>();
LinkedList<Integer> outbox = new LinkedList<Integer>(); // Push element x to the back of queue.
public void push(int x) {
inbox.push(x);
} // Removes the element from in front of queue.
public void pop() {
if (outbox.isEmpty()) {
while (!inbox.isEmpty()) {
outbox.push(inbox.pop());
}
}
outbox.pop();
} // Get the front element.
public int peek() {
if (outbox.isEmpty()) {
while (!inbox.isEmpty()) {
outbox.push(inbox.pop());
}
}
return outbox.peek();
} // Return whether the queue is empty.
public boolean empty() {
return inbox.isEmpty() && outbox.isEmpty();
}
}

4 总结

  • 巧妙的用两个statck实现queue,数据只存储一份,很好的考察基本的数据结构能力。
  • 由于题目假设poppeek都不会在队列为空的时候执行,避免了Null Pointer Exception.

5 参考