1 second
256 megabytes
standard input
standard output
Luckily, Serval got onto the right bus, and he came to the kindergarten on time. After coming to kindergarten, he found the toy bricks very funny.
He has a special interest to create difficult problems for others to solve. This time, with many 1×1×11×1×1 toy bricks, he builds up a 3-dimensional object. We can describe this object with a n×mn×m matrix, such that in each cell (i,j), there are hi,jhi,j bricks standing on the top of each other.
However, Serval doesn't give you any hi,j and just give you the front view, left view, and the top view of this object, and he is now asking you to restore the object. Note that in the front view, there are mm columns, and in the ii -th of them, the height is the maximum of h1,i,h2,i,…,hn,ih1,i,h2,i,…,hn,i . It is similar for the left view, where there are nn columns. And in the top view, there is an n×mn×m matrix ti,jti,j , where ti,jti,j is 00 or 11 . If ti,jti,j equals 11 , that means hi,j>0hi,j>0 , otherwise, hi,j=0hi,j=0 .
However, Serval is very lonely because others are bored about his unsolvable problems before, and refused to solve this one, although this time he promises there will be at least one object satisfying all the views. As his best friend, can you have a try?
The first line contains three positive space-separated integers n,m,hn,m,h (1≤n,m,h≤1001≤n,m,h≤100 ) — the length, width and height.
The second line contains mm non-negative space-separated integers a1,a2,…,ama1,a2,…,am , where aiai is the height in the ii -th column from left to right of the front view (0≤ai≤h0≤ai≤h ).
The third line contains nn non-negative space-separated integers b1,b2,…,bnb1,b2,…,bn (0≤bj≤h0≤bj≤h ), where bjbj is the height in the jj -th column from left to right of the left view.
Each of the following nn lines contains mm numbers, each is 00 or 11 , representing the top view, where jj -th number of ii -th row is 11 if hi,j>0hi,j>0 , and 00 otherwise.
It is guaranteed that there is at least one structure satisfying the input.
Output nn lines, each of them contains mm integers, the jj -th number in the ii -th line should be equal to the height in the corresponding position of the top view. If there are several objects satisfying the views, output any one of them.
3 7 3
2 3 0 0 2 0 1
2 1 3
1 0 0 0 1 0 0
0 0 0 0 0 0 1
1 1 0 0 0 0 0
1 0 0 0 2 0 0
0 0 0 0 0 0 1
2 3 0 0 0 0 0
4 5 5
3 5 2 0 4
4 2 5 4
0 0 0 0 1
1 0 1 0 0
0 1 0 0 0
1 1 1 0 0
0 0 0 0 4
1 0 2 0 0
0 5 0 0 0
3 4 1 0 0
解题思路：这道题就是给你正视图，侧视图，俯视图，让你恢复它的原状；
实际上这个用多组解；用贪心即可，每次取最小；
代码如下：
#include<iostream>
using namespace std; int row , col , height ;
int c[];
int r[];
int G[][];
int main()
{
cin>>row>>col>>height;
for(int i = ; i < col ;i++)
{
cin>>c[i];
}
for(int i = ; i < row ;i++)
{
cin>>r[i];
} for(int i = ; i < row ;i++)
{
for(int j = ; j < col ;j++)
{
cin>>G[i][j];
if(G[i][j]==)
{
if(c[j]<=r[i]) //不断取行和列交接处的较小者
{
G[i][j] = c[j];
}else
G[i][j] = r[i];
}
}
} for(int i = ; i < row ;i++)
{
for(int j = ; j < col ;j++)
{
cout<<G[i][j];
(j==col-)?cout<<"":cout<<" ";//格式
}
cout<<endl;
}
return ;
}