JSON数据与Java对象的相互转换

时间:2023-03-09 09:58:05
JSON数据与Java对象的相互转换

JSON数据与Java对象的相互转换

  • JSON解析器

    常见的解析器:Jsonlib 、Gson、 fastjson、 jackson

  1. JSON转化为Java对象

    1. 使用步骤:

      1、导入jackson的相关jar包
      2、创建jackson核心对象ObjectMapper
      3、使用ObjectMapper的相关方法进行转换
      1、readValue(json字符串数组,Class)
  2. Java转化为JSON对象

    1. 使用步骤

      1、导入jackson的相关jar包
      2、创建jackson核心对象ObjectMapper
      3、使用ObjectMapper的相关方法进行转换
      1. 转换方式:

         * writeValue(参数1,obj):
        参数1:
        File:将obj对象转换为JSON字符串,并保存到指定的文件中
        Writer:将obj对象转换为JSON字符串,并将json数据填充到字符输出流中
        OutputStream:将obj对象转换为JSON字符串,并将json数据填充到字节输出流中
        * writeValueAsString(obj):将对象转为json字符串
      2. 注解

        1. @JsonIgnore:排除属性。
      3. @JsonFormat:属性值得格式化

        • @JsonFormat(pattern = "yyyy-MM-dd")
        1. 复杂Java对象转换
          1. List:数组
          2. Map:对象格式一致

JSON数据与Java对象的相互转换

创建person类

public class Person {
private String name;
private Integer age;
private String gender;
//@JsonIgnore //忽略该属性
@JsonFormat(pattern = "yyyy-MM-dd")//属性格式化
private Date birthday; public Date getBirthday() {
return birthday;
} public void setBirthday(Date birthday) {
this.birthday = birthday;
}
public Person() {
} @Override
public String toString() {
return "Person{" +
"name='" + name + '\'' +
", age=" + age +
", gender='" + gender + '\'' +
'}';
} public String getName() {
return name;
} public void setName(String name) {
this.name = name;
} public Integer getAge() {
return age;
} public void setAge(Integer age) {
this.age = age;
} public String getGender() {
return gender;
} public void setGender(String gender) {
this.gender = gender;
}
}

Java转化为JSON对象

JacksonTest

public class JacksonTest {

 //Java对象转为JSON
@Test
public void test1() throws IOException {
//创建Person对象
Person person = new Person();
person.setName("张三");
person.setAge(21);
person.setGender("男");
ObjectMapper om = new ObjectMapper();
/*
writeValue(参数,obj)
参数1.:
File:将对象转换为json字符串,并保存指定的文件中
Writer:将对象转换为json字符串,并将json数据填充到字符输出流中
Outputstream:将对象转换为json字符串,并将json数据填充到字节输出流中
*/
/*//writeValue写到D://a.txt中
om.writeValue(new File("D://a.txt"),person);*/
//writeValue,数据关联到Writer中
// om.writeValue(new FileWriter("d://b.txt"),person); //将对象转化成json对象
String s = om.writeValueAsString(person);
System.out.println(s);
} @Test
public void test2() throws IOException {
//创建Person对象
Person person = new Person();
person.setName("张三");
person.setAge(21);
person.setGender("男");
person.setBirthday(new Date());
ObjectMapper om = new ObjectMapper();
String s = om.writeValueAsString(person);
System.out.println(s); } @Test
public void test3() throws IOException {
//创建Person对象
Person person = new Person();
person.setName("张三");
person.setAge(21);
person.setGender("男");
person.setBirthday(new Date());
//创建Person对象
Person person1 = new Person();
person1.setName("张三");
person1.setAge(21);
person1.setGender("男");
person1.setBirthday(new Date());
//创建Person对象
Person person2 = new Person();
person2.setName("张三");
person2.setAge(21);
person2.setGender("男");
person2.setBirthday(new Date()); //创建list集合
List<Person> list = new ArrayList<Person>();
list.add(person);
list.add(person1);
list.add(person2);
ObjectMapper om = new ObjectMapper();
String s = om.writeValueAsString(list);
System.out.println(s);
/**
* 输出结果:
* [{"name":"张三","age":21,"gender":"男","birthday":"2019-08-23"},
* {"name":"张三","age":21,"gender":"男","birthday":"2019-08-23"},
* {"name":"张三","age":21,"gender":"男","birthday":"2019-08-23"}]
*
*/ } @Test
public void test4() throws IOException {
Map<String,Object> map=new HashMap<String, Object>();
map.put("name","李四0");
map.put("age",23);
map.put("gender","男"); ObjectMapper om = new ObjectMapper();
String s = om.writeValueAsString(map);
System.out.println(s);
/**
* 输出结果:
* {"gender":"男","name":"李四0","age":23}
*/
}
}

JSON转化为Java对象

   public class JacksonTest {
@Test
public void test5() throws IOException {
//初始化
String json="{\"gender\":\"男\",\"name\":\"李四0\",\"age\":23}";
ObjectMapper ob=new ObjectMapper();
//转化为Java对象 person对象
Person person = ob.readValue(json, Person.class);
System.out.println(person);
}
}

案例--效验用户名是否存在

当文本输入框失去焦点,发送ajax请求,查询数据库中是否存在该用户

​ 存在:提示存在

​ 不存在:提示可用

1. 服务器响应的数据,在客户端使用时,要想当做json数据格式使用。有两种解决方案:
1. $.get(type):将最后一个参数type指定为"json"
2. 在服务器端设置MIME类型
response.setContentType("application/json;charset=utf-8");

效果图:

JSON数据与Java对象的相互转换

Servlet

import com.fasterxml.jackson.databind.ObjectMapper;

import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
import java.util.HashMap;
import java.util.Map; @WebServlet("/findUserServlet")
public class FindUserServlet extends HttpServlet {
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
//期望服务器响应回应的格式 {"userExsit":"true","msg":"用户名此用户名太受欢迎,请更换一个"}
// "userExsit":"false","msg":"用户名可用"}
Map<String, Object> map = new HashMap<String, Object>();
//设置相应格式为json
response.setContentType("application/json;charset=utf-8");
//获取用户名
String username = request.getParameter("username");
System.out.println(username);
//查询数据库
if ("tom".equals(username)) {
map.put("userExsit", true);
map.put("msg", "用户名此用户名太受欢迎,请更换一个"); } else {
map.put("userExsit", false);
map.put("msg", "用户名可用");
}
System.out.println(map);
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.writeValue(response.getWriter(), map); } protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
this.doPost(request, response);
}
}

html

<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
<style>
input {
padding: 10px;
margin: 5px;
} </style>
<script src="js/jquery-3.3.1.min.js"></script>
<script>
$(function () {
$("#username").blur(function () {
//获取username的值
var username = $(this).val(); //发送ajax请求
//期望服务器响应回应的格式 {"userExsit":"true","msg":"用户名此用户名太受欢迎,请更换一个"}
// "userExsit":"false","msg":"用户名可用"}
$.get("findUserServlet",{"username":username},function (data) { var span = $("#sp");
// 判断userExsit的值是否是true if (data.userExsit) {
//存在
span.html(data.msg) span.css("color", "red");
} else {
// 不存在
span.html(data.msg)
span.css("color", "green"); }
//1.
//},"json");
});
});
}) </script>
</head>
<body>
<div align="center">
<form action="" method="post">
用户名:<input type="text" id="username" name="username" placeholder="请输入用户名"><br><span id="sp" class="span"></span><br>
密&ensp;&ensp;码:<input type="password" name="password" placeholder="请输入密码"><br>
<input type="submit" value="注册">
</form>
</div>
</body>
</html>

源码地址GitHub:https://github.com/PoetryAndYou/JQuery