【BZOJ 1507】【NOI 2003】&【Tyvj P2388】Editor 块状链表模板题

时间:2023-03-08 21:26:26

2016-06-18 当时关于块状链表的想法是错误的,之前维护的是一个动态的$\sqrt{n}$,所以常数巨大,今天才知道原因TwT,请不要参照这个程序为模板!!!

模板题水啊水~~~

第一次写块状链表,先写一个模板题(⊙o⊙)

块状链表虽然效率大概在O(n√n),但它几乎没有常数,相比较理论上复杂度较快的O(nlogn)的Splay还是要快,因为Splay常数太大啦!感觉比较笨重。也许这就是许多OIer热衷分块的原因吧。

BZOJ 1507(因为O2优化,没有内存池)

#include<cmath>
#include<queue>
#include<cstdio>
#include<cstring>
#include<algorithm>
#define for1(i,a,n) for(int i=(a);i<=(n);++i)
#define for2(i,a,n) for(int i=(a);i<(n);++i)
#define for3(i,a,n) for(int i=(a);i>=(n);--i)
#define for4(i,a,n) for(int i=(a);i>(n);--i)
#define CC(i,a) memset(i,a,sizeof(i))
using namespace std;
int now=0,min_tot=0,max_tot=0,tot=0,sq;
struct BLOCK{
BLOCK();
BLOCK *next;
char c[100003];
int size;
}*head,*null;
BLOCK::BLOCK(){next=null;size=0;}
inline void build(){
null=new BLOCK;
*null=BLOCK();
head=new BLOCK;
}
inline BLOCK *find(int &k){
BLOCK *r=head;
while (k-r->size>0&&r->next!=null) k-=r->size,r=r->next;
return r;
}
inline void cut(BLOCK *r,int pos){
BLOCK *k=new BLOCK;
k->size=r->size-pos;
for1(i,pos+1,r->size) k->c[i-pos]=r->c[i];
r->size=pos;
k->next=r->next;
r->next=k;
}
inline void merge(BLOCK *r){
if (r->next==null) return;
BLOCK *k=r->next;
for1(i,1,k->size) r->c[r->size+i]=k->c[i];
r->size+=k->size;
r->next=k->next;
delete k;
}
inline void balance(){
BLOCK *r=head;
sq=floor(sqrt(tot)); min_tot=sq/2; max_tot=sq*2;
while (r!=null){
if (r->size<min_tot) if (r->next==null) return; else {merge(r); continue;}
else if (r->size>max_tot) {cut(r,r->size/2); continue;}
r=r->next;
}
}
inline void work1(int x){
int pnow=now; BLOCK *r=find(pnow),*k=new BLOCK,*sta=k;
cut(r,pnow);
for1(i,1,x){
char cs=getchar();
while (cs=='\n') cs=getchar();
k->size++; k->c[k->size]=cs;
if (k->size>=sq){
k->next=new BLOCK;
k=k->next;
}
}k->next=r->next;r->next=sta;
}
inline void work2(int x){
int pnow=now; BLOCK *r=find(pnow);
if (x<=r->size-pnow){
cut(r,pnow); cut(r->next,x);
BLOCK *xx=r->next;
r->next=r->next->next;
delete xx;
return;
}
x-=r->size-pnow;
cut(r,pnow);
BLOCK *xy=r->next;
r->next=r->next->next;
delete xy;
while (x-r->next->size>0&&r->next!=null){
x-=r->next->size;
BLOCK *xx=r->next;
r->next=r->next->next;
delete xx;
}cut(r->next,x);
BLOCK *xx=r->next;
r->next=r->next->next;
delete xx;
}
inline void work3(int x){
int pnow=now; BLOCK *r=find(pnow);
if (x<=r->size-pnow){for1(i,pnow+1,pnow+x) putchar(r->c[i]); return;}
for1(i,pnow+1,r->size) putchar(r->c[i]);
x-=r->size-pnow; r=r->next;
while (x-r->size>0&&r!=null){
for1(i,1,r->size) putchar(r->c[i]);
x-=r->size; r=r->next;
}for1(i,1,x)putchar(r->c[i]);
}
int main(){
build();
int n;scanf("%d\n",&n);
while (n--){
char str=getchar(),st=getchar();
int x;
switch(str){
case 'I':
while (st!=' ') st=getchar();
scanf("%d",&x); tot+=x; sq=floor(sqrt(tot)); min_tot=sq/2; max_tot=sq*2;
work1(x);
balance();
scanf("\n");
break;
case 'M':
while (st!=' ') st=getchar();
scanf("%d\n",&now);
break;
case 'D':
while (st!=' ') st=getchar();
scanf("%d\n",&x); work2(x);
tot-=x; balance();
break;
case 'G':
while (st!=' ') st=getchar();
scanf("%d\n",&x); work3(x); printf("\n");
break;
case 'P':
now--;st=getchar();st=getchar();st=getchar();
break;
case 'N':
now++;st=getchar();st=getchar();st=getchar();
break;
}
}
return 0;
}

Tyvj P2388(Windows下评测的new和delete慢得飞起,所以写了个内存池)

#include<cmath>
#include<queue>
#include<cstdio>
#include<cstring>
#include<algorithm>
#define for1(i,a,n) for(int i=(a);i<=(n);++i)
#define for2(i,a,n) for(int i=(a);i<(n);++i)
#define for3(i,a,n) for(int i=(a);i>=(n);--i)
#define for4(i,a,n) for(int i=(a);i>(n);--i)
#define CC(i,a) memset(i,a,sizeof(i))
using namespace std;
int now=0,min_tot=0,max_tot=0,tot=0,sq;
struct BLOCK{
BLOCK();
BLOCK *next;
char c[10003];
int size;
}*head,*null,pool[10003];
int top=0;
BLOCK::BLOCK(){next=null;size=0;}
inline BLOCK *newBLOCK(){
BLOCK *t=&pool[top++];
t->next=null; t->size=0;
return t;
}
inline void build(){
null=newBLOCK();
null->next=null; null->size=0;
head=newBLOCK();
}
inline BLOCK *find(int &k){
BLOCK *r=head;
while (k-r->size>0&&r->next!=null) k-=r->size,r=r->next;
return r;
}
inline void cut(BLOCK *r,int pos){
BLOCK *k=newBLOCK();
k->size=r->size-pos;
for1(i,pos+1,r->size) k->c[i-pos]=r->c[i];
r->size=pos;
k->next=r->next;
r->next=k;
}
inline void merge(BLOCK *r){
if (r->next==null) return;
BLOCK *k=r->next;
for1(i,1,k->size) r->c[r->size+i]=k->c[i];
r->size+=k->size;
r->next=k->next;
//delete k;
}
inline void balance(){
BLOCK *r=head;
sq=floor(sqrt(tot)); min_tot=sq/2; max_tot=sq*2;
while (r!=null){
if (r->size<min_tot) if (r->next==null) return; else {merge(r); continue;}
else if (r->size>max_tot) {cut(r,r->size/2); continue;}
r=r->next;
}
}
inline void work1(int x){
int pnow=now; BLOCK *r=find(pnow),*k=newBLOCK(),*sta=k;
cut(r,pnow);
for1(i,1,x){
char cs=getchar();
while (cs=='\n') cs=getchar();
k->size++; k->c[k->size]=cs;
if (k->size>=sq){
k->next=newBLOCK();
k=k->next;
}
}k->next=r->next;r->next=sta;
}
inline void work2(int x){
int pnow=now; BLOCK *r=find(pnow);
if (x<=r->size-pnow){
cut(r,pnow); cut(r->next,x);
BLOCK *xx=r->next;
r->next=r->next->next;
//delete xx;
return;
}
x-=r->size-pnow;
cut(r,pnow);
BLOCK *xy=r->next;
r->next=r->next->next;
//delete xy;
while (x-r->next->size>0&&r->next!=null){
x-=r->next->size;
BLOCK *xx=r->next;
r->next=r->next->next;
//delete xx;
}cut(r->next,x);
BLOCK *xx=r->next;
r->next=r->next->next;
//delete xx;
}
inline void work3(int x){
int pnow=now; BLOCK *r=find(pnow);
if (x<=r->size-pnow){for1(i,pnow+1,pnow+x) putchar(r->c[i]); return;}
for1(i,pnow+1,r->size) putchar(r->c[i]);
x-=r->size-pnow; r=r->next;
while (x-r->size>0&&r!=null){
for1(i,1,r->size) putchar(r->c[i]);
x-=r->size; r=r->next;
}for1(i,1,x)putchar(r->c[i]);
}
int main(){
build();
int n;scanf("%d\n",&n);
while (n--){
char str=getchar(),st=getchar();
int x;
switch(str){
case 'I':
while (st!=' ') st=getchar();
scanf("%d",&x); tot+=x; sq=floor(sqrt(tot)); min_tot=sq/2; max_tot=sq*2;
work1(x);
balance();
scanf("\n");
break;
case 'M':
while (st!=' ') st=getchar();
scanf("%d\n",&now);
break;
case 'D':
while (st!=' ') st=getchar();
scanf("%d\n",&x); work2(x);
tot-=x; balance();
break;
case 'G':
while (st!=' ') st=getchar();
scanf("%d\n",&x); work3(x); printf("\n");
break;
case 'P':
now--;st=getchar();st=getchar();st=getchar();
break;
case 'N':
now++;st=getchar();st=getchar();st=getchar();
break;
}
}
return 0;
}

分块真心强大,,,