canvas绘制二次贝塞尔曲线----演示二次贝塞尔四个参数的作用

时间:2023-03-09 18:07:54
canvas绘制二次贝塞尔曲线----演示二次贝塞尔四个参数的作用

canvas中绘制二次贝塞尔曲线的方法为ctx.quadraticCurveTo(x1,y1,x2,y2);

四个参数分别为两个控制点的坐标.开始点即当前canvas中目前的点,如果想从指定的点开始,需要使用ctx.moveTo(x,y)方法

演示效果如下图

canvas绘制二次贝塞尔曲线----演示二次贝塞尔四个参数的作用

上代码:

html

<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>无标题文档</title>
<style>
*{ margin:0; padding:0;}
#info{ width:800px; height:30px; line-height:30px; margin:50px auto 0 auto;}
#canvas{ display:block; border:1px solid #ccc; margin:0px auto;}
</style>
<script src="js/dot.js"></script>
<script src="js/main.js"></script>
</head> <body>
<div id="info"></div>
<canvas id="canvas" width="800" height="600"></canvas>
</body>
</html>

JS代码

dot.js

// JavaScript Document
var dot = function ( x , y ){
this.x = x;
this.y = y;
this.r = dotR;
}
dot.prototype.draw = function (ctx){
ctx.beginPath();
ctx.arc( this.x , this.y , this.r , 0 , Math.PI*2 );
ctx.fill();
ctx.closePath();
}

main.js

// JavaScript Document

var CANVERS_WIDTH = 800;
var CANVERS_HEIGHT = 600; var dotR = 10;
var dotArr = [];
window.onload = function(){ var oCanvas = document.querySelector("#canvas"); var oInfo = document.querySelector("#info"); var ctx = oCanvas.getContext("2d"); var dotA = new dot( 100 , 400 );
dotArr.push( dotA );
var dotB = new dot( 200 , 200 );
dotArr.push( dotB );
var dotC = new dot( 400 , 400 );
dotArr.push( dotC ); creatGuides();
createBezier(); function createBezier(){
ctx.beginPath();
ctx.moveTo( dotA.x , dotA.y );
ctx.quadraticCurveTo( dotB.x , dotB.y , dotC.x , dotC.y );
ctx.stroke();
ctx.closePath();
} //绘制辅助线 ctx.lineWidth = 2;
function creatGuides(){ dotA.draw( ctx );
dotB.draw( ctx );
dotC.draw( ctx ); ctx.beginPath();
ctx.moveTo( dotA.x, dotA.y );
ctx.lineTo( dotB.x , dotB.y );
ctx.lineTo( dotC.x , dotC.y );
ctx.stroke();
ctx.closePath(); } oCanvas.onmousedown = function (e){ var disX = e.clientX - this.offsetLeft;
var disY = e.clientY - this.offsetTop;
//判断鼠标放下是是否在控制点上
var curDot = checkDot(disX,disY) if( curDot ){ if(oCanvas.setCapture){ oCanvas.setCapture(); } document.onmousemove = function (e){ oInfo.textContent ="ctx.quadraticCurveTo("+ dotB.x + "," + dotB.y + "," + dotC.x + "," + dotC.y + ")"; disX = e.clientX - oCanvas.offsetLeft;
disY = e.clientY - oCanvas.offsetTop; curDot.x = disX;
curDot.y = disY; console.log(disX)
ctx.clearRect(0,0,CANVERS_WIDTH,CANVERS_HEIGHT);
creatGuides();
createBezier(); } document.onmouseup = function (){
creatGuides();
createBezier();
document.onmousemove = null;
document.onmouseup = null;
if(oCanvas.setCapture){ oCanvas.releasesCaptrue(); }
}
return false;
} } function checkDot(x,y){
for( var i=0; i<dotArr.length; i++ ){
if( Math.abs( dotArr[i].x - x ) < dotR && Math.abs( dotArr[i].y - y ) < dotR ){
return dotArr[i];
}
}
return false;
} }